Phillips received 75 points on a project. he can make changes and receive two tenths of the missing points back. He can make corrections as many times as he wants. Create the formula for the sum of the geometric series, and explain your steps in solving for the maximum grade Phillip can receive. Identify this as converging or diverging
@TheSmartOne
@perl
can we assume that the student got 75 points out of 100 points possible?
Sure
That's why I'm asking on here... Sorry :(
no problem :)
the missing points is 25 to start out
Okay
2/10 = 1/5 , in lowest form
Yup
I guess this helps, thanks :)
We start with 100 - 75 = 25 points For the first correction he can get 1/5 * 25 points. That leaves you with 4/5 * 25 points For the second correction he can get 1/5 * (4/5 * 25) points That leaves you with 4/5 * (1/5 * (4/5 * 25)) points
do you see a pattern emerging ?
Yeah
correction 1 : 1/5 * (4/5)^0 * 25 correction 2: 1/5 * (4/5)^1 * 25 correction 3: 1/5 * (4/5)^2 * 25 correction 4: 1/5 * (4/5)^3 * 25 . . . correction n: 1/5 * (4/5)^(n-1) * 25
We start with 100 - 75 = 25 points For the first correction he can get 1/5 * 25 points. That leaves you with 4/5 * 25 points For the second correction he can get 1/5 * (4/5 * 25) points That leaves you with 4/5 * (4/5 * 25)) points For the third correction he can get 1/5 * (4/5)^2 * 25 Leaving you with 4/5* (4/5)^2 * 25
2/10 is the same as 20% , so i subtracted from 100% to get 80% 80% = 80/100 = 4/5
Thanks @perl
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