Question

Graph r=theta^2

Answer 1

I understand how to graph \[\Large r=\theta\] but when I have r=theta^2, the r values don't match up to what I'm doing...

Answer 2

@SolomonZelman or @jim_thompson5910 ??

Answer 3

plug in arbitrary values for \[\theta\] and graph them and you will see. this is also the same thing as y=x^2

Answer 4

actually are you in polar coordinates?

Answer 5

yes that looks right if you're in polar

Answer 6

actually no sorry, because you won't have any negative values with theta^2

Answer 7

I saw a method that used the actual graph with the ind being theta and the dependent being r and then transfer info about it to the actual graph, it's kind of hard to explain, please look at this video to see what I'm saying (start at 5:51)

https://www.youtube.com/watch?v=E7oR_JBgUzA

Answer 8

I think you will have to go through point by point to see this one. I don't think there is an easy visualization for this. I'll try it out myself.

Answer 9

its a kind of spiral

Answer 10

Thing is, I understna dhwen you have r=theta, that the r length os where you're at, so when you hit the "negative" part of the x-axis, it will have a length of 3.14159 because the angle there is pi