Question

Can someone explain how I would solve this?

Answer 1

Rewrite the left hand side using the properties of exponents

Answer 2

or the right hand side, either works

Answer 3

Im not really sure what that is but i'll google it lol

Answer 4

\(\huge a^{-x}=\frac{1}{a^x}\)

Answer 5

Um.. ok. So does that mean a would be 32?

Answer 6

32 - 5?

Answer 7

if we're doing the left hand side, we'd rewrite \(m^{-5}=\frac{1}{m^5}\)

Answer 8

Oh okay

Answer 9

How would i solve that then

Answer 10

\(\huge \frac{1}{m^5}=\frac{1}{32}\)
m^5=32

Answer 11

Okay.. so theyre equal?

Answer 12

i dont get how i find what M is from that

Answer 13

given the original statement, yeah
You'd have to recognize that 32 is a power of 2. maybe use logs

Answer 14

idk what logs is either.

Answer 15

or use a calculator with a root button

Answer 16

do i divide 32 by 5 or?

Answer 17

\(m^5=32\)
\(\large m=32^{\frac{1}{5}}\)

Answer 18

no, the 5 is an exponent

Answer 19

you can rewrite 32 as 2^5, does that help?

Answer 20

no because idk what im supposed to do to solve this.