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Mathematics 9 Online
OpenStudy (anonymous):

Help would be awesome!

OpenStudy (anonymous):

yes @bradenhart

OpenStudy (solomonzelman):

it surely would be:)

OpenStudy (anonymous):

OpenStudy (solomonzelman):

the formula for an arithmetic sequence is as follows. \(\large\color{black}{ A_n=a_1+d(n-1) }\) where: ~ \(\large\color{black}{ A_n }\) is any nth term. ~ \(\large\color{black}{ a_1 }\) is the first term. ~ \(\large\color{black}{ d }\) is the difference (you add to obtain the next term) ~ \(\large\color{black}{ n }\) (in \(\large\color{black}{ a_n }\) ) is the number of the term.

OpenStudy (anonymous):

i think answer is c

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

am i right? @SolomonZelman

OpenStudy (solomonzelman):

you need: \(\large\color{black}{ a_1 }\), \(\large\color{black}{ a_4 }\) and \(\large\color{black}{ a_{10} }\)

OpenStudy (anonymous):

k

OpenStudy (anonymous):

ok! So its 12,21,39

OpenStudy (solomonzelman):

the answer was given away to be C, but we would check right?

OpenStudy (solomonzelman):

\(\large\color{black}{ a_{1} }\) is 12, as given by the formula in your question.

OpenStudy (solomonzelman):

\(\large\color{black}{ a_{4}=a_1+3(n-1)=12+3(4-1)=12+9=21 }\)

OpenStudy (solomonzelman):

\(\large\color{black}{ a_{10}=a_1+3(n-1)=12+3(10-1)=12+27=39 }\)

OpenStudy (anonymous):

thnx @SolomonZelman :]

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