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Mathematics 11 Online
OpenStudy (specek18):

In the equation n+5−−−−√−n−10−−−−−√=1, the value of n is

OpenStudy (specek18):

OpenStudy (specek18):

@satellite73

OpenStudy (anonymous):

probably 11

OpenStudy (anonymous):

you can solve this the math teacher way, but it is kind of a pain in the neck it is easier to guess

OpenStudy (specek18):

that was my guess too, but i have a feeling it should be way more complicated. lol

OpenStudy (anonymous):

here is the deal if \(n+5\) and \(n-10\) are both perfect squares, then there are not a lot of choices for \(n\)

OpenStudy (specek18):

okay...i went with 11 because i thought it'd equal 1 but i didnt enter it,...don't really know so does any one else have an opinion or idea?

OpenStudy (anonymous):

i focussed on \(n-10\) and though if \(n=11\) then \(n-10=1,n+5=16\) both squares but \(4-1=3\) so 11 is not right, lets move to the next possibility

OpenStudy (anonymous):

i it is not 11, lets try again

OpenStudy (jhannybean):

\[\sqrt{n-5} -\sqrt{n-10} = 1\]\[\sqrt{n-10} = \sqrt{n-5}-1\]\[n-10=n-5+2\sqrt{n-5}+1\ ...\]

OpenStudy (jhannybean):

Can't solve it in that method?

OpenStudy (anonymous):

think you might have made a small mistake

OpenStudy (anonymous):

\[n-10=n-5\color{red}-2\sqrt{n-5}+1\]

OpenStudy (specek18):

i'm so confused...lol

OpenStudy (jhannybean):

Ah yeah the negative.

OpenStudy (perl):

you can solve the equation by first adding `sqrt(n-10` to both sides then squaring both sides of the equation

OpenStudy (anonymous):

i still like the guess method how can \(n-10\) and \(n+5\) both be perfect squares?

OpenStudy (anonymous):

Ik ur not supposed to give the answer but walk them through and help them but its 59

OpenStudy (anonymous):

11 works there are not that many squares around 16 makes n = 26 25 makes n = 35 36 makes n = 46 49 makes n = 59 bingo, both 49 and 64 are perfect squares!

OpenStudy (specek18):

this is insane. lol so there can be more than one answer but it's not multiple choice???

OpenStudy (jhannybean):

\[n-10=n-5-2\sqrt{n-5}+1\]\[n-10=n-2\sqrt{n-5}-4\]\[6=-2\sqrt{n-5}\]\[-3=\sqrt{n-5}\]\[9=n-5\]Etc.

OpenStudy (anonymous):

there is and answer, it is 59

OpenStudy (anonymous):

*one answer

OpenStudy (specek18):

okay...i wrote down what @Jhannybean said and it's making a little more sense....thank you to everyone for helping me out and dealing with me!!! only 3 more questions...haha

OpenStudy (jhannybean):

@satellite73 can you elaborate on your guess and check method? I'd like to learn this.

OpenStudy (specek18):

i understood what you did @Jhannybean but i just sort of accepted that @satellite73 is a genius. lol i have no clue what she did either!

OpenStudy (jhannybean):

There's always time to learn new techniques :)

OpenStudy (specek18):

i was able to do the next two by myself but i have one left....

OpenStudy (jhannybean):

post it in a new question :)

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