In the equation n+5−−−−√−n−10−−−−−√=1, the value of n is
@satellite73
probably 11
you can solve this the math teacher way, but it is kind of a pain in the neck it is easier to guess
that was my guess too, but i have a feeling it should be way more complicated. lol
here is the deal if \(n+5\) and \(n-10\) are both perfect squares, then there are not a lot of choices for \(n\)
okay...i went with 11 because i thought it'd equal 1 but i didnt enter it,...don't really know so does any one else have an opinion or idea?
i focussed on \(n-10\) and though if \(n=11\) then \(n-10=1,n+5=16\) both squares but \(4-1=3\) so 11 is not right, lets move to the next possibility
i it is not 11, lets try again
\[\sqrt{n-5} -\sqrt{n-10} = 1\]\[\sqrt{n-10} = \sqrt{n-5}-1\]\[n-10=n-5+2\sqrt{n-5}+1\ ...\]
Can't solve it in that method?
think you might have made a small mistake
\[n-10=n-5\color{red}-2\sqrt{n-5}+1\]
i'm so confused...lol
Ah yeah the negative.
you can solve the equation by first adding `sqrt(n-10` to both sides then squaring both sides of the equation
i still like the guess method how can \(n-10\) and \(n+5\) both be perfect squares?
Ik ur not supposed to give the answer but walk them through and help them but its 59
11 works there are not that many squares around 16 makes n = 26 25 makes n = 35 36 makes n = 46 49 makes n = 59 bingo, both 49 and 64 are perfect squares!
this is insane. lol so there can be more than one answer but it's not multiple choice???
\[n-10=n-5-2\sqrt{n-5}+1\]\[n-10=n-2\sqrt{n-5}-4\]\[6=-2\sqrt{n-5}\]\[-3=\sqrt{n-5}\]\[9=n-5\]Etc.
there is and answer, it is 59
*one answer
okay...i wrote down what @Jhannybean said and it's making a little more sense....thank you to everyone for helping me out and dealing with me!!! only 3 more questions...haha
@satellite73 can you elaborate on your guess and check method? I'd like to learn this.
i understood what you did @Jhannybean but i just sort of accepted that @satellite73 is a genius. lol i have no clue what she did either!
There's always time to learn new techniques :)
i was able to do the next two by myself but i have one left....
post it in a new question :)
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