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Hey Guys! Can anyone help me, I'm kinda confused here. How many moles of calcium hydroxide are needed to produce 73.7 milliliters of water, if the density of water is 0.987 g/mL? Show all steps of your calculation as well as the final answer. HCl + Ca(OH) 2 → H2O + CaCl2
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first balance the equation 2 HCl + Ca(OH)2 --> 2 H2O + CaCl2
It isn't balanced already?
the mole ratio of calcium hydroxide : water is 1:2 (73.7 mL) x (0.987 g/mL) / (18.0153 g H2O/mol)=4.037 mole of water 4.037/2= 2.02 moles Ca(OH)2
Ohhhh I think I get it now...Thank you! Would you maybe have some study tips for Chemistry? I'm finding it difficult to grasp concepts.
just do every thing step by step
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Okay thank you
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