Question

@Abhisar
Write the complete balanced equation for the reaction between barium metal (Ba) and nitrogen gas (N2).

Answer 1

Let's start with what do you think...

Answer 2

@sleepyjess

Answer 3

\(\bf BaN_2\)?

Answer 4

Write down the complete equation..

Answer 5

\(\bf Ba+N_2~\rightarrow~BaN_2\)

Answer 6

When Barium reacts with dinitrogen (\(\sf N_2\)) then Barium Nitrate is formed. Valency of Nitrate is 3 and that of barium is 2. Now can rewrite the equation this time try to write it correct

Answer 7

I am thinking this, but you can't change the small numbers...
\(\bf Ba+N_2=Ba_3N_2\)

Answer 8

Yes, this is correct. You can't change the small numbers/subscripts while balancing the equation.

Answer 9

Now, we need to balance the equation.

Answer 10

\(\bf 3Ba+3N_2~\rightarrow~3BaN_2\)?

Answer 11

\(\bf \cancel{\bcancel{3Ba+3N_2~\rightarrow~3BaN_2}}\)?

Answer 12

:(

Answer 13

See what have you done, you cahnged the subscripts of \(\sf Ba_3N_2\).

Answer 14

But Ba didn't originally have a subscript.
It spells ban.....

Answer 15

This was your original equation
\(\bf Ba+N_2=Ba_3N_2\)

and you made it

\(\bf 3Ba+3N_2~\rightarrow~3BaN_2\)?

Answer 16

No, my original was \(\bf Ba+N_2~\rightarrow~BaN_2\) and then I said that I was thinking \(\bf Ba+N_2=Ba_3N_2\) but I can't change the subscripts.

Answer 17

Oh

Answer 18

\(\bf Ba+N_2~\rightarrow~BaN_2\) is wrong equation. We corrected it to \(\bf Ba+N_2=Ba_3N_2\). Now we need to balance it. Balance this equation with playing with the subscripts. Getting it?

Answer 19

\(\bf\color{red} 3Ba+N_2=Ba_3N_2\)

Answer 20

There you go

Answer 21

\(\huge \checkmark\)

Answer 22

:D

Answer 23

Still won't load on another tab :/

Answer 24

Remember these steps,

\(\square\) First write down the correct skeleton equation (You can change the subscripts in this step)
\(\square\) Balance the equation (can not play with the subscripts)