1/3x = 12 solve for x
you want to isolate x but oh no x is being multiplied by 1/3 to undo that multiplication you can divide both sides by 1/3
Do you mean \(\dfrac{1}{3} x = 12\) ?
yes @mathstudent55
|dw:1419383170042:dw| can u solve from there?
36
can't i just add 2/3 to both sides?
Ok. Since x is being multiplied by 1/3 and you want x alone, multiply both sides by the reciprocal of 1/3, which is 3.
great :D
No. Adding 2/3 will not help.
1/3 is multiplied so u gotta multiply it by the reciprocal
\(\dfrac{1}{3} x = 12\) Add 2/3 to both sides: \(\dfrac{1}{3} x + \dfrac{2}{3} = 12 + \dfrac{2}{3}\) \(\dfrac{1}{3} x + \dfrac{2}{3} = 12 \dfrac{2}{3}\) Since 1/3 x and 2/3 are not like terms, they can't be combined together, so you have just complicated the equation instead of solving it.
hmm, i'm thinking
where did u get 2/3 from @mindblast3r
The way to solve an equation is to do the opposite operation of what is being done to x. The opposite of multiplying by 1/3 is divide by 1/3, but dividing by 1/3 is the same as multiplying by 3.
I assume the idea was to do 1/3 + 2/3 = 1
yes lol @mathstudent55
well i know adding 2/3 was wrong but, my main intentions of the question was to find out why it's wrong, i just didn't know how to phrase the question.
I hope you understand it now.
The way to solve an equation is to do the opposite operation of what is being done to x. is this like an official rule?
No, I never heard of it as an officvial rule, but that's how we solve equations.
who is "we", humans?
Yes, "we" are people. Here is something for youto think about. Take an equation such as 2x + 5 = 15
i'll let @mathstudent55 help u :D
You want x alone, but there is a 5 being added and a 2 being multiplied.
thank you veryyyyyyyyyyyyyy much guys i <3 all of you
How do you figure out which exact operations to do to get rid of the plus 5 and the times 2?
Think of just the left side, 2x + 5. If you were asked to evaluate the left side for a number, such as x = 10, what would you do?
1. subtract 5 from both sides 2. divide both sides by 2 3. x = 5
First, you replace x with 10. 2x + 5 2(10) + 5 Now you do the multipluication first, 2 * 10 20 + 5 Finally youi do the aqddition, 20 + 5 25
You are correct.
Now look at what I did to evaluate the left side. 1) I first multiplied by 2 2) then I added 5
To solve the equation, you do the opposite operation in the opposite order. To Evaluate: To Solve: multiply by 2 subtract 5 add 5 divide by 2
okay i understand now. thank you :D
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