Determine how many, what type, and find the roots for f(x) = x^3 - 5x^2 – 25x + 125.
using the fundamental theorem of algebra - will medal
Factor x^3 - 5x^2 – 25x + 125 by grouping as follows: (x^3 - 5x^2) – (25x - 125)
ok, and then I find the gcf's?
Yes. GCF of x^3 and -5x^2. Then GCF of -25x and +125.
ok so that'll be x^2(x-5) and 25(x+5) ?
x^2(x-5) and -25(x-5)
oh ok. since the second part is negative, do I add the two?
f(x) = x^3 - 5x^2 – 25x + 125 = x^2(x - 5) - 25(x - 5) = (x^2 - 25)(x - 5) = (x + 5)(x - 5)(x - 5) = (x + 5)(x - 5)^2
To find the root, set f(x) = 0 and solve for x. (x+5)(x-5)^2 = 0 implies x = -5 or x = 5. The roots are: -5 and 5 (with multiplicity of 2).
ok, thank you! :)
You are welcome. How many roots? Two What type of roots? Two real roots Find the roots: -5 and 5. 5 has a multiplicity of two.
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