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Mathematics 10 Online
OpenStudy (anonymous):

check my answer please will medal A building manager installs sensors to see how often people turn of the lights when they leave a room. After a month the manager has sample size of 400, a sample mean of 47%, and a sample standard deviation of 4%. What is the confidence level for a confidence interval of 46.6 to 47.4 A99.7% B 85% C 68% D 95% I think it's d

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

Hi, I will try to help

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

The figures in your problem are inconsistent with the data. The sample std deviation is not and cannot be .04 (4%). the sample std dev is sqrt[(.47)(1-.47)/400]=.02495. The margin of error from your CI is .474 -.47= .004 (very small). This would represent .02495/.004= 6.24 std dev. from expected, which would have a very high level of confidence (99.99.. %). Something is likely wrong with the figures in your problem.

OpenStudy (anonymous):

@Dianie are you there

OpenStudy (anonymous):

@Dianie what is going on you are not answering me

OpenStudy (anonymous):

I gave you the answer: he figures in your problem are inconsistent with the data. The sample std deviation is not and cannot be .04 (4%). the sample std dev is sqrt[(.47)(1-.47)/400]=.02495. The margin of error from your CI is .474 -.47= .004 (very small). This would represent .02495/.004= 6.24 std dev. from expected, which would have a very high level of confidence (99.99.. %). Something is likely wrong with the figures in your problem. A. is the answer because it is close to 99.99%

OpenStudy (anonymous):

Ok how did you find that answer

OpenStudy (anonymous):

With my brain and I searched it on Google to double check so I copied it from Google.

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

why @satellite73

OpenStudy (anonymous):

I want at least two opinion to be completely sure thanks for the help

OpenStudy (anonymous):

your welcome but I will still stay

OpenStudy (fibonaccichick666):

Please read what she says Diane as she explained her reasoning. If you cannot read it, as seems plausible due to your rude response to help, please learn to read english or translate it using a convenient site like google translate.

OpenStudy (anonymous):

It is in English

OpenStudy (anonymous):

nto another language to have to translate it and google translate is not even right all the time

OpenStudy (anonymous):

Ok thank you again I get it now I saw it but I didn't understand it

OpenStudy (anonymous):

ooohhh

OpenStudy (fibonaccichick666):

then say that, it's a great way to have someone help you learn

OpenStudy (anonymous):

@FibonacciChick666 go away

OpenStudy (anonymous):

thanl you for saying that

OpenStudy (anonymous):

@Zarkon can you fan me so I can message you

OpenStudy (anonymous):

Thanks for the help but it was d

OpenStudy (anonymous):

Ohhh I am so sorry.

OpenStudy (fibonaccichick666):

You may like this reference: http://onlinestatbook.com/2/estimation/mean.html

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