Homework help please asap
f(x)= (x-3)^2 -2
Give the open interval on which the function is increasing .

Question

Homework help please asap 
f(x)= (x-3)^2 -2 
Give the open interval on which the function is increasing .

loser66 · Answer

Any idea?

loser66 · Answer

is it calculus or precalculus?

loser66 · Answer

Hopefully this graph rings something https://www.desmos.com/calculator/t1otqnrsnp

solomonzelman · Answer

First differentiate the function (take it's derivative). Tell me what you get.

solomonzelman · Answer

what is troubling you, please ask @ElleCullen .

anonymous · Answer

is it $$f(x)=(x-3)^2-2$$?

loser66 · Answer

@SolomonZelman  that's why I asked whether it is cal or precal. If the course is cal, then differentiate is the best way to solve. If it is precal, we must use graph to solve

solomonzelman · Answer

sure, but she is silent ... don't know why

anonymous · Answer

if so it is a parabola that opens up (because the leading coefficient is positive) so it will be increasing from the first coordinate of the vertex to infinity

solomonzelman · Answer

yes

anonymous · Answer

fortunately it is already in vertex form, so you needn't compute anything

ellecullen · Answer

It is PreCalculus. I am not ready for Calculus yet, This cource is what I am repeating since I don't want any problems in College if I make it .

ellecullen · Answer

I graphed this equation. I get--> an upward parabola. I don't understand how I must give the open interval on which the entire function is increasing. Could it be something of -2?

jim_thompson5910 · Answer

A function increases when the graph goes uphill as you read from left to right.

jim_thompson5910 · Answer

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jim_thompson5910 · Answer

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jim_thompson5910 · Answer

you can have a piece of a function (ie an interval) increase as well

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