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Mathematics 16 Online
OpenStudy (specek18):

find the least common denominator will give medal for correct answer:)

OpenStudy (specek18):

OpenStudy (misty1212):

wow you get a lot of attention!

OpenStudy (specek18):

@misty1212 i guess...i'm horrible at math is all, nothing special.

OpenStudy (anonymous):

We already factored one of them before.

OpenStudy (misty1212):

you gotta factor both denominators \[a^2+4a+4\] and \[a^2-3a-10\]

OpenStudy (misty1212):

@wio i bet it was the perfect square right? \(a^2+4a+4=(a+2)(a+2)\)

OpenStudy (specek18):

you did that so fast....@misty1212

OpenStudy (misty1212):

so what is left is to factor \[a^2-3a-10\] which will definitely have a factor of \(a+2\) in it

OpenStudy (specek18):

lol but i'm still writing it out...i did get/ understand what you got!

OpenStudy (fibonaccichick666):

You just learned how to do this from wio, please show us your attempts

OpenStudy (misty1212):

that means the second one is going to be \[(a+2)(binomial)\] i am sure you can find it without too much agony `

OpenStudy (fibonaccichick666):

Please let them try @misty1212 , you are doing the problem for them.

OpenStudy (specek18):

(a+2) again?

OpenStudy (misty1212):

ok bye

OpenStudy (anonymous):

They are assuming that \(a+2\) is going to be the GCD.

OpenStudy (anonymous):

GCF

OpenStudy (fibonaccichick666):

Well, what did you factor both of them into?

OpenStudy (anonymous):

But if you didn't make that assumption, you would factor \(-10\).

OpenStudy (anonymous):

We want \(ab=-10\) and \(a+b=-3\).

OpenStudy (specek18):

(a+2) (a-5)? after being factored??

OpenStudy (anonymous):

Yes

OpenStudy (specek18):

then what....?

OpenStudy (anonymous):

Now, what is the GCF?

OpenStudy (fibonaccichick666):

(what term goes into both factorizations?)

undeadknight26 (undeadknight26):

Isnt it just that? Im actually rusty on these things myself...just asking the smart peoples ._.

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