find the least common denominator will give medal for correct answer:)
wow you get a lot of attention!
@misty1212 i guess...i'm horrible at math is all, nothing special.
We already factored one of them before.
you gotta factor both denominators \[a^2+4a+4\] and \[a^2-3a-10\]
@wio i bet it was the perfect square right? \(a^2+4a+4=(a+2)(a+2)\)
you did that so fast....@misty1212
so what is left is to factor \[a^2-3a-10\] which will definitely have a factor of \(a+2\) in it
lol but i'm still writing it out...i did get/ understand what you got!
You just learned how to do this from wio, please show us your attempts
that means the second one is going to be \[(a+2)(binomial)\] i am sure you can find it without too much agony `
Please let them try @misty1212 , you are doing the problem for them.
(a+2) again?
ok bye
They are assuming that \(a+2\) is going to be the GCD.
GCF
Well, what did you factor both of them into?
But if you didn't make that assumption, you would factor \(-10\).
We want \(ab=-10\) and \(a+b=-3\).
(a+2) (a-5)? after being factored??
Yes
then what....?
Now, what is the GCF?
(what term goes into both factorizations?)
Isnt it just that? Im actually rusty on these things myself...just asking the smart peoples ._.
Join our real-time social learning platform and learn together with your friends!