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Mathematics 12 Online
OpenStudy (anonymous):

(calculus) Two parter about the mean value of a function.

OpenStudy (anonymous):

OpenStudy (anonymous):

For the mean value I ended up getting 450/7 but I'm pretty that's wrong. And for part b I'm not quite sure where to begin. It looks like I need to take the integral or something, but we haven't learned those yet. Just derivatives.

OpenStudy (anonymous):

Yup, and that's where I got 450/7. I don't know if that's even the right formula to be using, though.

OpenStudy (anonymous):

Hmm so that's the answer to the first part? Because I thought that formula gave you the average rate of change but not the average value of the entire function.

OpenStudy (perl):

oh it says mean value, not average rate of change

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

I haven't learned anything about integrals yet because we've only studied derivatives

OpenStudy (anonymous):

I understand. But my school gave me this question without teaching a single thing about integration. The only thing I can think to do is solve for f(0) through f(12) and dividing by 12. And even that will only be an estimation

OpenStudy (anonymous):

They say mean value, but I think they mean the mean value of the derivative (average rate of change).

OpenStudy (perl):

ok it should say mean value of S ' (t)

OpenStudy (perl):

the mean value of S ' (t) on the interval is equivalent to the average rate of change of S(t) on the interval, and so you used the formula correctly and got 450/7

OpenStudy (anonymous):

Hmm, alright. So what would I do for part b? Derive the equation and then set it equal to 450/7?

OpenStudy (perl):

correct

OpenStudy (perl):

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