Question

Factor completely 5c5 + 60c4 + 180c3.
5c3(c + 6)(c - 6)
5c3(c2 + 12c + 36)
5c3(c + 6)2
5(c + 6)2

Answer 1

\(\large\color{black}{ 5c^5 + 60c^4 + 180c^3 }\)

Answer 2

In each of the terms, you have a common multiple/factor of: \(\large\color{black}{ 5c^{~3} }\) . Try to factor out of it, for me please.

Answer 3

okay ill try

Answer 4

take your time if need to.

Answer 5

\[5c5+60c4+180c3\]

Answer 6

\[c3\left( 5c2+12c +36 \right)\]

Answer 7

did i do that correctly?

Answer 8

i feel like i messed up with the 5c2 and the c3

Answer 9

you mean, \(\large\color{black}{ 5c^{~3}(c^{~2} + 12c+ 36) }\)

Answer 10

yes thats what i was going to put but i didnt know i should have gone with my gut feeling

Answer 11

okay so let me break it down again

Answer 12

i can divide 12 and 36 by 6 to factor is completely right or am i doing it wrong again?

Answer 13

yes, factor the inside.

Answer 14

Factor: \(\large\color{black}{ c^{~2} + 12c+ 36 }\)

Answer 15

yes!!!! sorry im just happy im getting it lol

Answer 16

you know that 6+6=12, and 6*6=36.

Answer 17

\[c2+6c +6\]

Answer 18

right?

Answer 19

\(\large\color{black}{ c^{~2} + 12c+ 36 = }\) \(\large\color{black}{ c^{~2} + 6c+6c+ 36 =c(c+6)+6(c+6)=? }\)

Answer 20

ohhhh

Answer 21

yes, so \(\large\color{black}{ c^{~2} + 12c+ 36 }\) is factored into?

Answer 22

a

Answer 23

how do you have any negative factors in \(\large\color{black}{ c^{~2} + 12c+ 36 }\) , if all the terms of this trinomial are positive?

Answer 24

If I had: b(b+5)+5(b+5) , I would combine this to: (b+5)(b+5)

Answer 25

c idk i'm close to giving up

Answer 26

C is correct actually

Answer 27

\(\large\color{black}{ 5c^{~3}(c^{~2} + 12c+ 36) }\)
\(\large\color{black}{ 5c^{~3}(c+6) ^{~2} }\)

Answer 28

well i was going in between that and a. im sorry for being a little out of it. i just really dont get it. lol thank you though for keeping up with me :)

Answer 29

yw