Simplify.
\[\frac{ \sqrt[3]{7} }{\sqrt[5]{7}}\]
\(\Large\color{black}{ \sqrt[\color{blue}{{\huge c}}]{a^{~\color{red}{{\huge b}}}} ~~~~\Rightarrow~~~~ a^{(\color{red}{{\huge b}}/\color{blue}{{\huge c}})}}\)
and b is an understood 1 right?
no
please do apply the aforementioned rule for me on top and bottom. and tell me what you get after doing this.
\[\frac{ 7\frac{ 1 }{ 3 } }{ 7 \frac{ 1 }{ 5 } }\] ?
yes.
now apply the: \(\large\color{black}{ \frac{\LARGE a^{\color{red}{b}}}{\LARGE a^{\color{blue}{c}}}=a^{\LARGE \color{red}{b}-\color{blue}{c}} }\)
\[7^{3-5}\]
not exactly, your power on the top is 1/3, and the power on the bottom is 1/5.
you can draw it if you want to, I mean if latex is an onus
I dont know where I went wrong
would I be subtracting the fractions?
yes, \(\large\color{black}{ 7^{^\color{blue}{{\frac{\LARGE 1 }{\LARGE 3}-\color{red}{{\frac{\LARGE 1 }{\LARGE 5}}}}}} }\)
\[\frac{ 2 }{ 15 }\]
yes 7^(2/15)
oh ok thanks!
yw
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