Question

Part A: If (6^2)^x = 1, what is the value of x?
Part B: If (6^0)^x = 1, what are the possible values of x?

Answer 1

just U should know
\[(6^{2})^{x}=6^{2x}\]

Answer 2

Do you know why what M_A said is true @ImNotLostLikeYou ?

Answer 3

\[6^{?}=1\]

Answer 4

i'm struggling with no useful help

Answer 5

a couple of rules you might want to know for this problem:

~ \(\large\color{black}{ (a^{b})^c=a^{~b \times c}}\)
~ \(\large\color{black}{ a^0=1}\) (when \(\large\color{red}{ a \ne 0}\) )

Answer 6

uh...

Answer 7

So, can you tell us what you don't understand? A little more in depth so we know where to start from

Answer 8

your first problem is: \(\large\color{black}{ (6^2)^x=1}\) apply the 1st rule to it.

Answer 9

the letter times a letter and equals to a letter

Answer 10

i want to know how to find what the letter means

Answer 11

ok, so, a letter, is just a variable. It's a place holder. We use it because it means we can pick ANY numbers and put the number in place of the variable, and the result is always true

Answer 12

oh ok.

Answer 13

Can you please read these few pages, I think they may help you with the background info necessary for this problem http://www.purplemath.com/modules/exponent.htm

Answer 14

There are like 5 pages, but the first one should clarify the rules Solomon posted

Answer 15

I want to find the missing exponent not the missing base

Answer 16

I wouldn't necessarily want to solve the second one, because 1^a=1 , a is all numbers

Answer 17

but we can at least bear with the first problem

Answer 18

Those rules are necessary to find x values

Answer 19

Which solomon just pointed out, for part two

Answer 20

You need to know how to simplify an exponentil expression to an exponent before you can do either problem

Answer 21

If I had: \(\large\color{black}{ (4^3)^c=1}\) then you would rewirte it as: \(\large\color{black}{ 4^{3c}=1}\)

So if i had: If I had: \(\large\color{black}{ (6^2)^x=1}\) how would i then write it?

Answer 22

Part A Answer: x = 0??

Answer 23

Please answer Solomon's posed wuestion @ImNotLostLikeYou

Answer 24

6^2z

Answer 25

yes.

Answer 26

z is a typo I know

Answer 27

so now, you have \[6^{2x}=1\]

Answer 28

then take the log of both sides

Answer 29

im confused, I have to find the variable of x not z?

Answer 30

and one more rule you need: \(\large\color{black}{ \log(a^b)~~~~\Rightarrow ~~~~b~\log(a)}\)

Answer 31

well, you said that it is z.

Answer 32

I mean that it is x.

Answer 33

It's just a variable, a placeholder