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Mathematics 21 Online
OpenStudy (anonymous):

What is the center of the circle that has a diameter whose endpoints are (6, -4) and (18, 10)? a.(12, 7) b.(12, 6) c.(12, 3)

OpenStudy (dtan5457):

Use the midpoint formula

OpenStudy (dtan5457):

c.(12, 3)

OpenStudy (dtan5457):

(6+18)/2=12 (-4+10)/2=3

OpenStudy (anonymous):

thx what about What is the center of the circle that has a diameter whose endpoints are (-3, -5) and (-11, -7)? a.(-8, -1) b.(-7, -6) c.(-4, -6)

OpenStudy (dtan5457):

the diameter of a circle is the same from any point as long as it crosses the center, so just midpoint it

OpenStudy (dtan5457):

again you midpoint that

OpenStudy (dtan5457):

x1+x2 divided by 2 y1+y2 divided by 2

OpenStudy (dtan5457):

you wanna try that?

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