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What is the center of the circle that has a diameter whose endpoints are (6, -4) and (18, 10)? a.(12, 7) b.(12, 6) c.(12, 3)
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Use the midpoint formula
c.(12, 3)
(6+18)/2=12 (-4+10)/2=3
thx what about What is the center of the circle that has a diameter whose endpoints are (-3, -5) and (-11, -7)? a.(-8, -1) b.(-7, -6) c.(-4, -6)
the diameter of a circle is the same from any point as long as it crosses the center, so just midpoint it
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again you midpoint that
x1+x2 divided by 2 y1+y2 divided by 2
you wanna try that?
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