How many moles of calcium hydroxide are needed to produce 73.7 milliliters of water, if the density of water is 0.987 g/mL?

HCl + Ca(OH) 2 → H2O + CaCl2

Question

How many moles of calcium hydroxide are needed to produce 73.7 milliliters of water, if the density of water is 0.987 g/mL? 

HCl + Ca(OH) 2 → H2O + CaCl2

sleepyjess · Answer

@Abhisar

sleepyjess · Answer

Is this like the one we just did?

abhisar · Answer

Yes...

sleepyjess · Answer

Calcium hydroxide is the CaCl2 right?

abhisar · Answer

Nopes, that's Calcium chloride. Hydroxide is OH, so calcium hydroxide is Ca(OH)2

sleepyjess · Answer

Yeah I just realized that :)

abhisar · Answer

First Step:
Balance the equation.

danjs · Answer

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danjs · Answer

2HCL  +  Ca(OH)2 ----->  2H2O  + CaCl2

danjs · Answer

Just multiplying the initial given information (73.7 mL H2O)  by ratios of 1, notice the units cancel leaving Mol Ca(OH)2

danjs · Answer

The Mole ratio in the 4th fraction is from the balanced chemical equation.

abhisar · Answer

Is it done?

danjs · Answer

I think so. It just asked for the moles of calcium hydroxide needed to produce that much water.