Question

Find the nonpermissible replacement for the variable in this expression.

5x/ 6x+3 thats 5x over 6x+3

Answer 1

a. -2

b. - 1/2

c. 0

d. 1/2

Answer 2

I don't really get what the problem is like.

Answer 3

just this, \(\large\color{black}{ \frac{\LARGE 5x}{\LARGE 6x+3} }\) ?

Answer 4

okay, the non-permissible replacement is an x-value at which the expression is undefined.

Answer 5

if the denominator is zero, then the expression is undefined. So let me ask you:

When x equals what , does the denominator equal 0?

Answer 6

(set the denominator equal to zero, and solve for x)

Answer 7

i got 0

Answer 8

it might seem as thought that you are trying to guess the answer. Please don't. You can ask if you don't get something, and I will attempt my best to explain this, but again please don't try to guess the....

So this is what we are doing here:

\(\large\color{black}{ \frac{\LARGE 5x}{\LARGE 6x+3} }\). We know that; \(\large\color{black}{ \frac{\rm anything}{\LARGE 0}=\rm undefined }\)

So, to find the values where \(\large\color{black}{ \frac{\LARGE 5x}{\LARGE 6x+3} }\) you need to equate \(\large\color{black}{ 6x+3 }\) to \(\large\color{black}{ 0 }\) .

\(\large\color{black}{ 6x+3=0 }\) .

can you solve for x?

Answer 9

-1/2

Answer 10

excuse me, to find the values *where \(\large\color{black}{ \frac{\LARGE 5x}{\LARGE 6x+3} }\) is undefined, you need to equate...

Answer 11

yes

Answer 12

-1/2 is correct