A railroad tunnel is shaped like a semiellipse as shown below. A semiellipse is shown on the coordinate plane with vertices on the x axis and one point of intersection with the positive y axis. The height of the tunnel at the center is 58 ft and the vertical clearance must be 29 ft at a point 21 ft from the center. Find an equation for the ellipse.
@bohotness please help?:)
vertex= (0, 58) h= 0 k= 58 ive got this so far do you know where I could go from here?:)
what is the standard form of an ellipse equation, itll give us something to start filling in
do you known it ?
(x - h)^2 = 4p(y - k), p ≠ 0
\[\frac{ (x - h)^2 }{ a^2 } + \frac{ (y-k)^2 }{ b^2 } = 1\]
a and b are your Semi-major axis lengths
You are given 2 points
(x-h^2)/a^2+(y-k)^2/b^2=1
OH WAIT sorry I gave you the formula for a parabola:/
its okay
Consider (0,0) the center of the elipse (0,58) is on the ellipse (21,29) is another point on the ellipse
ok well I know one of the points is (0, 58) and I guess I could assume that another point is (0, -58)...
and the h,k parts are 0 since we want to center it. the under y part is the height at the center, squared.
all thats left to do is determine the value of a. any ideas?
right so 58 is your a or b value
semi-major axis length , center to the parahelion
b is the height stated in the problem, it is the distance from center to the y vertex ...
when y=b, then b^2/b^2 = 1
so, h=k=0 to center it at the origin of the graph ... and b=58 as stated. any ideas to determine a?
you can figure out the remaining value, if a = 58, and (h,k) =(0,0) Find the value for 'b'
well I though 58 was = a because its the major axis
we have reduced it to one equation with 1 unknown, and a known point.
it would be the 'b' under the Y term
use the point and solve for a
rewrite your standard equation but with h=k=0 and b=58
\[\frac{ 21^2 }{ a^2 } + \frac{ 29^2 }{ 58^2 }= 1\]
it a = 588?
It will be the Positive root answer, it is a distance
I got \[a = 14\sqrt{3} \approx 24.25\]
YA that's what I got when I square rooted 588:) thanks so much:)
yw
yeah so a^2 = (14 root 3)^2
yw
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