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Mathematics 21 Online
OpenStudy (anonymous):

A railroad tunnel is shaped like a semiellipse as shown below. A semiellipse is shown on the coordinate plane with vertices on the x axis and one point of intersection with the positive y axis. The height of the tunnel at the center is 58 ft and the vertical clearance must be 29 ft at a point 21 ft from the center. Find an equation for the ellipse.

OpenStudy (anonymous):

OpenStudy (anonymous):

@bohotness please help?:)

OpenStudy (anonymous):

vertex= (0, 58) h= 0 k= 58 ive got this so far do you know where I could go from here?:)

OpenStudy (bohotness):

what is the standard form of an ellipse equation, itll give us something to start filling in

OpenStudy (bohotness):

do you known it ?

OpenStudy (anonymous):

(x - h)^2 = 4p(y - k), p ≠ 0

OpenStudy (danjs):

\[\frac{ (x - h)^2 }{ a^2 } + \frac{ (y-k)^2 }{ b^2 } = 1\]

OpenStudy (danjs):

a and b are your Semi-major axis lengths

OpenStudy (danjs):

You are given 2 points

OpenStudy (bohotness):

(x-h^2)/a^2+(y-k)^2/b^2=1

OpenStudy (anonymous):

OH WAIT sorry I gave you the formula for a parabola:/

OpenStudy (bohotness):

its okay

OpenStudy (danjs):

Consider (0,0) the center of the elipse (0,58) is on the ellipse (21,29) is another point on the ellipse

OpenStudy (anonymous):

ok well I know one of the points is (0, 58) and I guess I could assume that another point is (0, -58)...

OpenStudy (bohotness):

and the h,k parts are 0 since we want to center it. the under y part is the height at the center, squared.

OpenStudy (bohotness):

all thats left to do is determine the value of a. any ideas?

OpenStudy (danjs):

right so 58 is your a or b value

OpenStudy (danjs):

semi-major axis length , center to the parahelion

OpenStudy (bohotness):

b is the height stated in the problem, it is the distance from center to the y vertex ...

OpenStudy (bohotness):

when y=b, then b^2/b^2 = 1

OpenStudy (bohotness):

so, h=k=0 to center it at the origin of the graph ... and b=58 as stated. any ideas to determine a?

OpenStudy (danjs):

you can figure out the remaining value, if a = 58, and (h,k) =(0,0) Find the value for 'b'

OpenStudy (anonymous):

well I though 58 was = a because its the major axis

OpenStudy (bohotness):

we have reduced it to one equation with 1 unknown, and a known point.

OpenStudy (danjs):

it would be the 'b' under the Y term

OpenStudy (bohotness):

use the point and solve for a

OpenStudy (bohotness):

rewrite your standard equation but with h=k=0 and b=58

OpenStudy (danjs):

\[\frac{ 21^2 }{ a^2 } + \frac{ 29^2 }{ 58^2 }= 1\]

OpenStudy (anonymous):

it a = 588?

OpenStudy (danjs):

It will be the Positive root answer, it is a distance

OpenStudy (danjs):

I got \[a = 14\sqrt{3} \approx 24.25\]

OpenStudy (anonymous):

YA that's what I got when I square rooted 588:) thanks so much:)

OpenStudy (bohotness):

yw

OpenStudy (danjs):

yeah so a^2 = (14 root 3)^2

OpenStudy (danjs):

yw

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