Question

Someone refresh me on this. How do I write a quadratic equation knowing that the sum of roots are 6 and product of roots are -27?

Answer 1

@SolomonZelman

Answer 2

@satellite73

Answer 3

ax^2-(sum of roots)x+(product of roots)=0

Answer 4

think about what you do when you factor

Answer 5

also what @MARC_ said, but make the leading coefficient 1

Answer 6

so x^2-(-27)x+(6)=0?

Answer 7

oh no

Answer 8

product of the roots is the constant

Answer 9

you got it backwards

Answer 10

yup

Answer 11

oh, so switch numbers

so you get x^2+6x-27?

Answer 12

as the final equation?

Answer 13

\[x^2-6x-24=0\]

Answer 14

ur sign is wrong @dtan5457

Answer 15

@satellite73 -27, not -24 :)

Answer 16

-(sum of roots)x

wouldn't that be -6x?

Answer 17

it suppose be x^2-6x-27

Answer 18

i didn't write -6x did i

Answer 19

yup

Answer 20

so ax^2-(sum of roots)x+(product of roots)=0 is the formula for any question like this?

Answer 21

yes @dtan5457