Fun question If f(0) = f(1) = 0 and f" exists, show that
\[\int\limits_{0}^{1} f''(x)f(x)dx = - \int\limits_{0}^{1} [f'(x)]^2 dx\] shouldn't be too bad :)
LOL
Alright what if you combine \(f''(x)f(x) \implies (f'''(x)dx)\) then do the chain rule twice?
something like that.
Hmm.
My initial thought:\[ (ff')' = f'f'+ff'' \]
That's where I was going with it.
Guess triple prime wasn't needed.
by parts !
wio U are right
(ff')=(f')^2+ff"
\[\int\limits_{0}^{1} f''(x)f(x)dx = f'(x)f(x)\Bigg|_{0}^1 - \int \limits_0^1 f'(x) f'(x) dx\]
We know that: \[ \int_0^2 (f(x)f'(x))'dx=\int_0^1d\bigg(f(x)f'(x)\bigg)= 0f'(2)-0f'(0)= 0 \]
And oo:\[\int\limits_{0}^{1} f''(x)f(x)dx +\int\limits_{0}^{1} [f'(x)]^2 dx = 0\]
and so
@iambatman Is this enough?
Yes, that's enough haha, maybe next time I'll have a no ganeshie rule! :P
What? I came up with the anti-derivative first thought...
though Laptop keyboard is unreliable
lol ask tough questions instead
shots fired
It wasn't suppose to be tough :(, just fun
pew pew
Guess, I'll find some questions related to eliassaab's haha, if you want a real challenge :P
I think we exceeded the quota for number theory this week, im eager to do more calc post more questions batman xD
Haha, well mhm, I'll have to find/ think of some tricky ones for calc...I will see :D, and I agree there have been many number theory questions the past week D:
does\( f(x)=xsin(\pi x)\) satisfies it
is it twice differentiable ?
yes i think
yes it satisfies the hypothesis so both integrals need to evaluate to same numbers
nice you're looking for counter examples ;p http://www.wolframalpha.com/input/?i=%5Cint_0%5E1+%28xsin%28pi+x%29%29%27%27*%28xsin%28pi+x%29%29+dx++%3D+-%5Cint_0%5E1+%28%28xsin%28pi+x%29%29%27%29%5E2dx
That's neat haha
Post questions involving Vieta's Formula so I can LEARN how to use it!!!!
was yesterday's drill useful jhanny ?
....Hah. <_<
Haven't heard of that in a while lol
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