PLZZZ HELP ME ANYONE?!!?!!!?
with what mate
i'll post the question right now
The function f(x) = 20(3)x represents the growth of a fish population every year in a local lake. Jesse wants to manipulate the formula to an equivalent form that calculates every half-year, not every year. Which function is correct for Jesse's purposes? f(x) = 20(3)the x over 2 power f(x) = 20(3 to the one half power)2x f(x) = twenty halves(3)x f(x) = 40(2)x
Let me rewrite your answers because they are not making sense to me.
ok
A. \(f(x) = 20(3)\left(\frac{x}{2}\right)\) B. \(f(x) = 20(3^{1/2})(2x)\) C. \(f(x) = \left(\frac{20}{2}\right)3x\) D. \(f(x) =40(2)x\)
I think that the Xs are supposed to be x powers.....I am in algebra 2 and I am doing this right now and that is what is is for mine.....
ok so your original formula was \(f(x) = 20(3)^x\)?
Cand D are to the x power @Jhannybean
The function \[f(x) = 20(3)^x\] represents the growth of a fish population every year in a local lake. Jesse wants to manipulate the formula to an equivalent form that calculates every half-year, not every year. Which function is correct for Jesse's purposes? \[A. f(x)=20(3)^{\frac{ x }{ 2 }}\] \[B. f(x)=20(3^{\frac{ 1 }{ 2 }})^{2x}\] \[C. f(x)=\frac{ 20 }{ 2 }(3)^x\] \[D. f(x)=40(2)^x\] @iamabarbiegirl does this look correct?
yes @haleyelizabeth2017
Okay. Just making sure....that should help in the correct format :)
Ok that makes much much more sense.
sorry about that lol @Jhannybean
your variable \(x\) represents the time .
You want to find an equation that represents the growth of a fish population every HALF year, so how would you represent that?
1 year = \(x\), \(\dfrac{1}{2}\) year = ?
i'm really confused.. idk any of this and i'm in a hurry i need to submit this asap
@mathstudent55 @iambatman
in other words, it would be \(^{1/2x}\) which is the same as \(^{x/2}\)
there is only one option that is like that....
so A? @haleyelizabeth2017
Ding ding ding, we have a winner!!! :)
hahah than kyou sooooo sooo much!
yup yup, no problem. But don't thank me....@Jhannybean did all the work :)
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