Question

Divide 1/3(a^3b^4) by 2/3(a^2b)

Answer 1

\[\frac{ 1 }{ 3 } a^3b^4 \div \frac{ 2 }{ 3 } a^2b\]

Answer 2

rewrite as a multiplication of the reciprocal of the right and then cancel accordingly

Answer 3

\(\huge \frac{a^m}{a^n}=a^{m-n}\)

Answer 4

also worth noting \(\huge \frac{2}{3}a^2b=\frac{2a^2b}{3}\)

Answer 5

group like terms its easier to "see"
when you divide by a fraction invert the divisor and multiply
rules of exponents already posted above; when you divide numbers or variables with the same base subtract the exponents

Answer 6

so basically reciprocal the 2/3 to 3/2 and then just divide normally?

Answer 7

multiply

Answer 8

\(\large \frac{a}{b} \div \frac{c}{d}= \frac{a}{b}*\frac{d}{c}\)

Answer 9

ok, but the terms a and b, divide them right?

Answer 10

in this case a is (a^3b^4) and b is 3

Answer 11

1/2 ab^3

Answer 12

my point is \(\frac{1}{2} ab^3=\frac{ab^3}{2} \)

Answer 13

then for the variables
a^3/a^2 = a^(3-2) = a^1
b^4/b= b^(4-1)= b^3

so altogether 1/2ab^3

good job!

Answer 14

oh I'm stupid

Answer 15

i got it now

Answer 16

thanks guys

Answer 17

since you are learning exponents and using same bases
you might want to not work with fractions like elementary but for this problem use base of 3
1/3 = 3^-1 divide by 2*3^-1
what you have is 1/2* 3^-1-(-1) so it become 1/2 * 3^(-1 + 1)
anything raised to the power 0 = 1
so 1/2 *3^0 = 1/2 *1 = 1/2