The height and width of a cuboid are each increased by 10% and its length is decreased by 10%. The percentage increase in volume is?

Question

crashonce · Answer

@perl

danjs · Answer

Volume of Cuboid = L*W*H 

right?

crashonce · Answer

yes

danjs · Answer

Height increases --  (H + 0.1H)
Width Increases --- (W + 0.1W)
Length Decreases --- (L - 0.1L)

danjs · Answer

Multiply those values 
100% Volume = L x W x H
x% volume = ....

danjs · Answer

Modified Volume = (1.089)(L x W x H)

danjs · Answer

Modified Volume / 100% Volume =

danjs · Answer

You could also try using numbers,, let original L, W, and H = 10, and the modified versions
H = 11
W = 11
L = 9

Calculate and find the percent diff

danjs · Answer

$$\frac{ Modified }{ Original } = \frac{ 11 * 11 * 9 }{ 10^3 } = \frac{ 1189 }{ 1000 } \approx 1.089$$

danjs · Answer

modified is 108.9 percent the original volume

danjs · Answer

sound good?

crashonce · Answer

yes thanks