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Mathematics 13 Online
OpenStudy (anonymous):

There are two similar right triangles, ABC, and CBD. Line AC = 6, angle A = 30 degrees. What is the length of line DB?

OpenStudy (anonymous):

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OpenStudy (danjs):

ok, you can find CB from the bigger triangle

OpenStudy (danjs):

tan(30) = CB / 6

OpenStudy (danjs):

angle b = 180 - 90 - 30 = 60

OpenStudy (danjs):

cos 60 = DB / CB

OpenStudy (danjs):

CB = 6 tan(30) DB = CB*cos(60) = 6*tan(30)*cos(60) = .....

OpenStudy (danjs):

you follow that , or need more explanation?

OpenStudy (anonymous):

bruh...

OpenStudy (danjs):

?

OpenStudy (anonymous):

I don't know how to find CB. Can you give me an equation to figure it out?

OpenStudy (danjs):

yeah Do you remember the tangent Tangent(angle) = opposite side / adjacent side

OpenStudy (danjs):

Tan(a) = CB / AC

OpenStudy (danjs):

They gave you angle a=30 , and side AC = 6,

OpenStudy (anonymous):

Hang on.

OpenStudy (anonymous):

(.5774)(30)=180/4?

OpenStudy (anonymous):

* 180/6

OpenStudy (danjs):

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OpenStudy (anonymous):

Sorry, that was stupid.

OpenStudy (danjs):

CB = 6*tan(30) = approx 3.464

OpenStudy (anonymous):

Okay I'm with you.

OpenStudy (danjs):

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OpenStudy (danjs):

You see how i put the 60 degrees for angle b?

OpenStudy (anonymous):

Yeah

OpenStudy (danjs):

The sum of the angles for a triangle is 180 degrees. 180 = a + b + c

OpenStudy (danjs):

Then to get DB , you can use the cosine Cos(60) = adjacent / hypotenuse cos(60) = DB / 3.464 DB = 3.464*cos(60)

OpenStudy (anonymous):

\[\sqrt{3}\]

OpenStudy (danjs):

? what is that for

OpenStudy (anonymous):

Is that the answer? 1.73?

OpenStudy (danjs):

yep!

OpenStudy (anonymous):

Thank you for your time and effort! I appreciate it!! :)

OpenStudy (danjs):

if you dont use decimals...

OpenStudy (danjs):

DB = 6*tan(30)*cos(60) = \[6*\frac{ \sqrt{3} }{ 3 }*\frac{ 1 }{ 2 }\] = DB = \[DB = \sqrt{3}~~ \approx 1.73\]

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