Question

Algebra II Help (Medal)
Equation below:

Answer 1

2/(4+ square root 6) - 2/(4-square root 6)

Answer 2

please, you have to razionalize both your terms.
For example, I multiply both numerator and denominator of your first term, by
4-sqrt(6):
namely:
\[\frac{ 2 }{ 4+\sqrt{6} }=\frac{ 2(4-\sqrt{6}) }{ (4+\sqrt{6})(4-\sqrt{6}) }=\]

Answer 3

\[=\frac{ 2(4-\sqrt{6}) }{ 16-6 }=\frac{ 2(4-\sqrt{6}) }{ 10 }=\frac{ 4-\sqrt{6} }{ 5 }\]

Answer 4

Now, please do the same with your second term, namely multiply both numerator and denominator, by 4+sqrt(6) @haleholmes

Answer 5

\[\frac{ 8+\sqrt{12} }{ 16-6 }\]

Answer 6

I got:
\[\frac{ 8+2\sqrt{6} }{ 10 }\]

Answer 7

I was going to post the more simplified one but my computer was being mean. Alright, now I subtract right?

Answer 8

yes!

Answer 9

one sec

Answer 10

please, keep in mind that your second term is, after simplification:
\[\frac{ 4+\sqrt{6} }{ 5 }\]

Answer 11

\[4 + \sqrt{6}\]

Answer 12

please note that you have to do this calculus:
\[\frac{ 4-\sqrt{6} }{ 5 }-\frac{ 4+\sqrt{6} }{ 5 }=...\]

Answer 13

I have no idea

Answer 14

what is the problem?

Answer 15

The calculus. What do I do with that?

Answer 16

common least multiple is 5, so we have:
\[\frac{ (4-\sqrt{6})-(4+\sqrt{6}) }{ 5 }=\frac{ 4-\sqrt{6}-4+\sqrt{6} }{ 5 }=...\]

Answer 17

please, what is the result?

Answer 18

It looks like the top just cancels out

Answer 19

oops I have made an error...

Answer 20

\[\frac{ (4-\sqrt{6})-(4+\sqrt{6} )}{ 5 }=\frac{ 4-\sqrt{6}-4-\sqrt{6} }{ 5 }=...\]

Answer 21

please, what is the result?

Answer 22

Its being annoying one more sec