Question

How many grams of sodium oxide can be produced when 55.3 g Na react with 64.3 g O2?

Unbalanced equation: \(\sf Na + O_2 \rightarrow Na_2O\)

Answer 1

Balanced equation (I think)
\(\sf\color{red}{4}Na+O_2\rightarrow\color{blue}{2}Na_2O\)

Answer 2

Limiting reactant ?

Answer 3

That is the right balanced equation

Answer 4

What are the molar masses of each of the reactants and products

Answer 5

\(\sf O_2=32\\Na=22.9898\\Na_2O=54.9898\)

Answer 6

starting with 55.3 grams sodium, change to moles sodium, use mole ratio from equation, then change moles sodium oxide to grams

Answer 7

you get that part?

Answer 8

\(\sf 55.3*\dfrac{1~mol}{22.9898}\)?

Answer 9

the second fraction is the molar mass of sodium, 22.9898 grams per 1 mole

Answer 10

see the grams cancel out, you are left with moles of sodium

Answer 11

That is the conversion right?

Answer 12

right, so after the first fraction, you have moles sodium , then the next fraction changes that to moles of sodium oxide

Answer 13

\(\approx 2.41\)

Answer 14

You dont have to calculate each one individually. set up your fractions so that the units cancel out, and get to the final unit you are looking for before you calculate any numbers

Answer 15

Like above is 4 fractions, units all cancel to leave you with grams of calcium oxide

Answer 16

just multiply all the top numbers, then divide by all the bottom numbers

Answer 17

I got 2.88

Answer 18

wait i think your number for Na2O molar mass is wrong...

Answer 19

2 Na =45.98
1 O = 16

molar mass Na2O = 61.98 grams per mole

Answer 20

Now I got 74.54 :/

Answer 21

right , so that is for the Na reactant, now we have to do the same for the O2 reactant and see how much product will be produced

Answer 22

Wouldn't you add the 2?