Question

If sinAcosA = 1/3, then 1/sinA^2 + 1/cosA^2 = ?
@satellite73

Answer 1

start off by manupilating 1/sin^2+1/cos^2
if you did common denominator you should get (cos^2A+sin^2A)/sinAcosA
and we know that cos^2+sin^2=1
and they gave us sinAcosA=1/3

Answer 2

just put things in their place and you got what you are looking for

Answer 3

eh that denominator should be sin^2Acos^2A

Answer 4

hehe i just realize i didn't square them lol

Answer 5

if you are wondering how to get squares
just square both sides of sinAcosA=1/3 meaning (sinAcosA)^2=(1/3)^2
which is the same as sin^2Acos^2A=1/9

Answer 6

you have everything now just plug in the values

Answer 7

wait so its 1/3? @xapproachesinfinity

Answer 8

\(\large\tt \begin{align} \color{black}{\dfrac{1}{sin^2A}+\dfrac{1}{cos^2A}\\~\\
=\dfrac{cos^2A+sin^2A}{sin^2Acos^2A}\\~\\
=\dfrac{1}{(sinAcosA)^2}\\~\\
}\end{align}\)