How would I graph a line with a slope of 2/3?

Question

danjs · Answer

start at the origin as your first point

danjs · Answer

slope = (change in y value) / change in x value) =2/3

nincompoop · Answer

slope = change in y divided by change in x 
m = 2/3

nincompoop · Answer

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nincompoop · Answer

You don't have to start from (0,0). You can start anywhere, but it is just convenient if we did it from (0,0)

danjs · Answer

just use 

y = (2/3)*x   and pick values for x  to get points(x,y)

nincompoop · Answer

$\sf slope = \frac{\Delta y}{\Delta x} = \frac{y_2-y_1}{x_2-x_1} = \frac{2-0}{3-0}=\frac{2}{3} $

pooja195 · Answer

Thank you @nincompoop  and @DanJS  it seems alot more easier :)

danjs · Answer

If you want to move the line up or down then use any number b in, 

y = (2/3)*x + b

danjs · Answer

welcome

nincompoop · Answer

@DanJS don't get too ahead with the point-slope form, she is merely learning slope itself

danjs · Answer

oh, beg my pard

pooja195 · Answer

actually I know all this stuff I just dont know how to graph rise over run which now get :)

nincompoop · Answer

>.< 
rise/run is just a mnemonic devise

nincompoop · Answer

I'd be damned if you knew linear equation already and not know how graph a slope