Mathematics
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OpenStudy (crashonce):
If x does not equal 0 and 1/x, log10x, x^3 are in GP, which of the following are true?
1) log x = x-1
2)log 10 x= x^2
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OpenStudy (crashonce):
@mathmath333
OpenStudy (mathmath333):
what do u know about geometric mean
OpenStudy (mathmath333):
if \(a,b~and~c\) are in geometric progreassion then
\(\dfrac{b}{a}=\dfrac{c}{b}\)
OpenStudy (crashonce):
that's correct
OpenStudy (mathmath333):
apply the same to your variables
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OpenStudy (crashonce):
how does that help with finding x tho
OpenStudy (mathmath333):
we dont want to find x ,we just have to check if the options are correct or not
OpenStudy (crashonce):
so how do I apply them
OpenStudy (mathmath333):
\(\large\tt \begin{align} \color{black}{\dfrac{1}{x},log 10x, x^3\\~\\
a,b,c
}\end{align}\)
\(\large\tt \begin{align} \color{black}{a=\dfrac{1}{x},b=log 10x,c= x^3\\~\\
}\end{align}\)
OpenStudy (crashonce):
oh right
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OpenStudy (crashonce):
log10x^2 = x^2
OpenStudy (crashonce):
therefore log 10x = x
OpenStudy (mathmath333):
so can u simplify it further
OpenStudy (mathmath333):
\(log(ab)=log(a)+log(b)\)
OpenStudy (crashonce):
1+x^2?
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OpenStudy (mathmath333):
what is \[\log{10x} \]
OpenStudy (crashonce):
x
OpenStudy (mathmath333):
\[\log(10x)=\log10+\log x\]btw what is the base of the log
OpenStudy (crashonce):
base 10
OpenStudy (mathmath333):
ok so u got the answer ?
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OpenStudy (crashonce):
no I don't get it what is it
OpenStudy (mathmath333):
\[we~found ~that~[\log(10x)=x]\]
OpenStudy (crashonce):
yes but which option confirms it
OpenStudy (mathmath333):
\[\log_{10} 10+\log_{10} x=x\]
OpenStudy (mathmath333):
what is \[\log_{10} 10=\]
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OpenStudy (crashonce):
1 no I get it but im not sure whichanswer it hints to
OpenStudy (mathmath333):
\(1\)+\(logx\)=\(x\)
OpenStudy (mathmath333):
i think it is equivalent to option \(a.\)
OpenStudy (mathmath333):
i mean option \(1.\)
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OpenStudy (jhannybean):
Just solve for \(\log(x)\) now, lol.