Question

A spring has a spring constant of 100 N/m, and the mass hanging on it is 0.71 kg. What is the period of the spring's motion?

0.031 s, 0.44 s, 0.53 s, or 1.0 s

***I am doing 1/2pi*sq.rt(100/.71) = f
and then T=1/f=1/18.64=0.053 but that's not a choice? what did i do wrong? thank you!

Answer 1

please note that the formula used to find the period T of a mass m attached to a spring with costant k, is:
\[T=2 \pi \sqrt{\frac{ m }{ K }}\]

Answer 2

ohh okay, so 2pi*sqrt(.71/100) ?

Answer 3

yes!

Answer 4

ohh! so i get 0.52? rounds to 0.50? is that correct? :)

Answer 5

I think 0.53 is better!

Answer 6

ah okay! thank you:)

Answer 7

thank you! :)