**PLEASE HELP** Verify that parallelogram ABCD with vertices A(-5, -1), B(-9, 6), C(-1,5), and D(3,-2) is a rhombus by showing that it is a parallelogram with perpendicular diagonals.
@jim_thompson5910
use distamce formula sqrt((x1-x2)^2+(y1-y2)^2) to count the dstance. The wrte eqaution of diagonals and verify thats their slopes are negative reciprocals
You need to show that the slope of the line AC multiplied by the slope of the line BD is equal to -1
two lines are perpendicular if the product of their slopes equals -1
Okay... So now im more confused...
A(-5, -1), C(-1,5) what is the slope of the line through A and C
use the slope formula \[\Large m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\]
4, -6?? @jim_thompson5910
Slope of the line through point A and point C \[\Large m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\] \[\Large m = \frac{5-(-1)}{-1-(-5)}\] \[\Large m = \frac{5+1}{-1+5}\] \[\Large m = \frac{6}{4}\] \[\Large m = \frac{3}{2}\]
I made (x1,y1) be point A (-5,-1) I made (x2,y2) be point B (-1,5)
hopefully it makes sense?
So what do i say for the answer? (x1,y1) be point A (-5,-1) (x2,y2) be point B (-1,5) ???
@jim_thompson5910
we want to find the slope of line AC that's why I made A the point (x1,y1) and C the point (x2,y2)
I'm not dealing with point B right now
AC is one diagonal BD is the other diagonal (we'll focus on that later)
Okay.. So what are we focusing on right now?
finding the slope of AC
I want to make sure you understand
asnaseer has a good pic drawn above
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