Which expression is equivalent to
\[\sqrt[3]{27n^5m^3p^2}\]
A) \[2n^\frac{ 3 }{ 5 }mn^ \frac{ 2 }{ 3}\]
recall the cubed root is the same as to the 1/3 power
quick note
and @DanJS notes faster than me lol
\[[27n^5m^3p^2]^{1/3}\]
you dont have to write the answers out, we can figure it out
Oh okay
do you remember \[[x^a]^b = x ^{a*b}\]
a power raised to another power, you can multiply the powers together
Yes i think ,
\[27^{1/3} * n ^{5 * 1/3} *m ^{3 * 1/3} * p ^{2*1/3}\] you see how each power was multiplied by 1/3
for example \[[n^5]^{1/3} = n ^{5 * 1/3} = n ^{5/3}\]
Yes i see.
ok , do that for the other 2 variables, m and p
and for the 27, it probably would be easier to understand leaving it as a cubed root rather than to the 1/3 power cubed root of 27 means, "what number multiplied by itself 3 times is 27"
27 = x * x * x
3 ?
right , so \[\sqrt[3]{27} = 3\]and we found the n is n^(5/3)
now you just have to multiply the m and p variables powers by 1/3 also
\[\sqrt[3]{27} * n ^{5/3} *m ^{3/3} * p ^{2/3}\]
just have to simplify those
m^(3/3) = m^1 = m
p^(2/3) is simplified as much as you can
Thank you so much i really appreciate it.
cool, you understand the two rules used here? nth root of a quantity is the same quantity to the 1/nth power variable raised to a power raised to a power = variable raised to the powers multiplied
Yep
cool, glad to help
Join our real-time social learning platform and learn together with your friends!