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Mathematics 20 Online
OpenStudy (anonymous):

Which expression is equivalent to

OpenStudy (anonymous):

\[\sqrt[3]{27n^5m^3p^2}\]

OpenStudy (anonymous):

A) \[2n^\frac{ 3 }{ 5 }mn^ \frac{ 2 }{ 3}\]

OpenStudy (danjs):

recall the cubed root is the same as to the 1/3 power

OpenStudy (dtan5457):

quick note

OpenStudy (dtan5457):

and @DanJS notes faster than me lol

OpenStudy (danjs):

\[[27n^5m^3p^2]^{1/3}\]

OpenStudy (danjs):

you dont have to write the answers out, we can figure it out

OpenStudy (anonymous):

Oh okay

OpenStudy (danjs):

do you remember \[[x^a]^b = x ^{a*b}\]

OpenStudy (danjs):

a power raised to another power, you can multiply the powers together

OpenStudy (anonymous):

Yes i think ,

OpenStudy (danjs):

\[27^{1/3} * n ^{5 * 1/3} *m ^{3 * 1/3} * p ^{2*1/3}\] you see how each power was multiplied by 1/3

OpenStudy (danjs):

for example \[[n^5]^{1/3} = n ^{5 * 1/3} = n ^{5/3}\]

OpenStudy (anonymous):

Yes i see.

OpenStudy (danjs):

ok , do that for the other 2 variables, m and p

OpenStudy (danjs):

and for the 27, it probably would be easier to understand leaving it as a cubed root rather than to the 1/3 power cubed root of 27 means, "what number multiplied by itself 3 times is 27"

OpenStudy (danjs):

27 = x * x * x

OpenStudy (anonymous):

3 ?

OpenStudy (danjs):

right , so \[\sqrt[3]{27} = 3\]and we found the n is n^(5/3)

OpenStudy (danjs):

now you just have to multiply the m and p variables powers by 1/3 also

OpenStudy (danjs):

\[\sqrt[3]{27} * n ^{5/3} *m ^{3/3} * p ^{2/3}\]

OpenStudy (danjs):

just have to simplify those

OpenStudy (danjs):

m^(3/3) = m^1 = m

OpenStudy (danjs):

p^(2/3) is simplified as much as you can

OpenStudy (anonymous):

Thank you so much i really appreciate it.

OpenStudy (danjs):

cool, you understand the two rules used here? nth root of a quantity is the same quantity to the 1/nth power variable raised to a power raised to a power = variable raised to the powers multiplied

OpenStudy (anonymous):

Yep

OpenStudy (danjs):

cool, glad to help

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