Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (crashonce):

Two circles with centres H and K are 12 cm apart, the radii are 4cm and 8 cm respectively, touching externally. PQT is a tangent to both circles. If angle HTP is A, then what are sin A, cos A and tanA

OpenStudy (crashonce):

|dw:1419736691204:dw|

OpenStudy (crashonce):

@jim_thompson5910 @ganeshie8

OpenStudy (anonymous):

|dw:1419737407037:dw|

OpenStudy (anonymous):

they have a common angle so you know the triangles are similar

OpenStudy (anonymous):

so you'll want to set up a ratio and from that you can create an equation to find x

OpenStudy (crashonce):

yes but that doesn't exactly help @mathmath333

OpenStudy (jhannybean):

Oh it helps plenty, actually. You have two similar triangles now. \(\triangle TPK\) and \(\triangle TQH\)

OpenStudy (crashonce):

I know and I tried that, does it actually work?

OpenStudy (jhannybean):

|dw:1419741400052:dw|

OpenStudy (jhannybean):

The radius is the perpendicular bisector of the line TP

OpenStudy (mathmath333):

\[\triangle THQ \sim \triangle TKP\\So\\ \frac{ TH }{ HQ }=\frac{ TK }{ KP }\\\frac{ TH }{ 4 }=\frac{ TH+HK }{ 8 }\\\frac{ TH }{ 4 }=\frac{ TH+12 }{ 8 }\\\]

OpenStudy (jhannybean):

\[\frac{x+12}{8}=\frac{x}{4}\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!