does this converge or diverge? If the sequence does converge, what number do the terms of the sequence converge to?

Question

jessicawade · Answer

$$a^n=(-1)^n100*n \over 100+n$$

thesmartone · Answer

$\Large a^n=$$\Large \frac{(-1)^n100*n}{100+n}$

jessicawade · Answer

yes

jessicawade · Answer

do you knwo?

thesmartone · Answer

I would say diverges... not sure though.. :/

jessicawade · Answer

oh hmm

thesmartone · Answer

https://www.khanacademy.org/math/integral-calculus/sequences_series_approx_calc/seq-conv-diverg/v/identifying-sequence-convergence-divergence

thesmartone · Answer

the last example is pretty helpful... http://www.wolframalpha.com/widgets/view.jsp?id=a787670f0f1047d7fbe288763c55ba14

thesmartone · Answer

so i would say Divierge @jessicawade

thesmartone · Answer

$\color{blue}{\text{Originally Posted by}}$ @TheSmartOne the last example is pretty helpful... http://www.wolframalpha.com/widgets/view.jsp?id=a787670f0f1047d7fbe288763c55ba14 $\color{blue}{\text{End of Quote}}$ Referring to the last example in Khan's video.

perl · Answer

it does not converge because of the (-1)^n , it alternates. 
The absolute terms of the sequence converge to 100, but the (-1)^n makes it alternate 

so for very large n you have the sequence  ... , -99.99, 99.999, -99.9999,  etc

thesmartone · Answer

Yup exactly like the last example in Khan's video I gave :P