Question

Two dice are thrown. If one shows a three, what is the probability that the total is less than 7

Answer 1

@MARC_ @ganeshie8

Answer 2

the chances of getting less than 7 for the second dice is 1,2 and 3 @CrashOnce

Answer 3

there are how many numbers in a dice? @CrashOnce

Answer 4

it's 6 @CrashOnce

Answer 5

so the chances of getting less than 7 have 3 numbers which is 1,2 and 3 @CrashOnce

Answer 6

\[=\frac{ 3 }{ 6 }\]
\[=?\]
solve it @CrashOnce

Answer 7

the answer options are: 1/6, 1/12, 5/11, 7/11, 5/36

Answer 8

Let's think about this.

Answer 9

Dice Toss Outcomes

Answer 10

5/11

Answer 11

thaks

Answer 12

Look at this

Answer 13

so it's 5/36

Answer 14

36 possibilities for outcomes, 5 have a 3 and another die totally less than 7.

Answer 15

count the number of outcomes which are less than 7 total

Answer 16

I agree @MARC_

Answer 17

so is it \(5/11\)

Answer 18

How are you figuring that @mathmath333

Answer 19

oh i see the first dice is given 3 already

Answer 20

If this is conditional probability, your answer may be correct. Let me re-read the problem.

Answer 21

yes its \(5/36\)

Answer 22

thnx @Directrix

Answer 23

I'll stick with the 5/36 because at the outset, the dice were first thrown which gave 6*6 outcomes. AFTER that, we were told about the three turning up and so on.