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OpenStudy (anonymous):
I'm stuck: (x+y)^2/4x^2-y^2 =?? if x = 3, y = -5d. I got (3-5d)^2/26-(-5d)^2. I tried simplifying it even further but things got messy.
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OpenStudy (anonymous):
is the eq (x+y)^2/(4x^2) -y^2
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
x=3 and y =-5d
(3+5d)^2/(4(3)^2)-(-5d)^2
OpenStudy (anonymous):
common denominator is 36
OpenStudy (anonymous):
so (3+5d)^2/36-(-5d)^2*36/36
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OpenStudy (anonymous):
One question, shouldn't it be: (x+y)^2 = (3+(-5d))^2 = (3-5d)^2? Since a positive and a negative makes a negative?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
you are right.....
OpenStudy (anonymous):
but in this case there is a squared
OpenStudy (anonymous):
(x+y)^2=(3-5d)^2
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OpenStudy (anonymous):
[(9-30d+25d^2)-(36*25d^2)]/36
OpenStudy (anonymous):
is that okay
OpenStudy (anonymous):
Okay, I'm getting it. I got 9-30d+25d^2/36+25d^2. Still trying to figure out the 36 part.
OpenStudy (anonymous):
Doesn't 25d^2 cancle each other out?
OpenStudy (anonymous):
no.... common denominator first
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OpenStudy (anonymous):
Okay, one thing you answered with [(9-30d+25d^2)-(36*25d^2)]/36. Multiplication on the 2nd parenthesis not addition?
OpenStudy (anonymous):
you need to multiply both upper and lower fraction by the same number which in this case 36 for a common denominator
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