Question

PLEASE HELP ON ALGEBRA 1 QUESTION
Don't just give answer.. explain plz :)
Medal + Fan

Answer 1

3x3y + 12xy - 3x2y - 12y

Part A: Rewrite the expression so that the GCF is factored completely.

Answer 2

Ok - look carefully at all the terms in your equation - can you see anything that appears in ALL the terms?

Answer 3

e.g. does \(x\) appear in every term in your expression?

Answer 4

Oh gimme a sec, the equation looks a bit messed up :D

Answer 5

It's really supposed to be (3x^3)y + 12xy - (3x^2)y - 12y

Answer 6

Is this your equation?\[3x^3y+12xy-3x^2y-12y\]

Answer 7

Yeah :)

Answer 8

Ok - so lets start with \(x\) - does it appear in EVERY term of the expression?

Answer 9

No, not in the last one

Answer 10

good - so that rules it out as a GCF

Answer 11

now look at \(y\) - does it appear in EVERY term of the expression?

Answer 12

Ah.... YES

Answer 13

so now what you need to do is to factor out a \(y\) from each term - do you know how to do that?

Answer 14

No, can you teach me :D

Answer 15

now this is exactly how your supposed to help someone with their homework...good job

Answer 16

don't forget the common number...not just the variable

Answer 17

Are you complementing me or asnaseer ;P

Answer 18

@texaschic101 - thx :)

Ok - first lets rewrite each term as follows:\[3x^3y+12xy-3x^2y-12y=y(3x^3)+y(12x)-y(3x^2)-y(12)\]does that make sense so far?

Answer 19

I am complimenting both of you

Answer 20

Thanks :)

And, ah... yes it does, you just removed the y's :D

Answer 21

Good - now we can take this COMMON \(y\) write out and rewrite the expression as follows:\[3x^3y+12xy-3x^2y-12y=y(3x^3)+y(12x)-y(3x^2)-y(12)\]\[=y(3x^3+12x-3x^2-12)\]agreed?

Answer 22

Did you take the equation without the y's and multiplied it all by a single y?

Answer 23

yes - the \(y\) outside will multiply by each term inside the brackets

Answer 24

think of it like this:\[2*3=2*(1+2)=2(1+2)=2*1+2*2=2+4=6\]

Answer 25

Ah ok....

Answer 26

this is called distributing the factor

Answer 27

Ok - now look at what remains inside the brackets:\[3x^3+12x-3x^2-12\]Can you see if there is any number that divides into every single term?

Answer 28

Yes 3

Answer 29

good - so now we do the same trick and write this as:\[3x^3+12x-3x^2-12=3(x^3)+3(4x)-3(x^2)-3(4)\]\[=3(x^3+4x-x^2-4)\]agreed?

Answer 30

Yes :)

Answer 31

great - no lets combine everything that we done to get:\[3x^3y+12xy-3x^2y-12y=y(3x^3+12x-3x^2-12)=3y(x^3+4x-x^2-4)\]

Answer 32

I hope that all makes sense

Answer 33

the final term is supposed to be:\[=3y(x^3+4x-x^2-4)\]

Answer 34

OH GOLLY SO MANY DIGITS, but uh yeah it does make sense :D

Answer 35

good :)

Answer 36

Alrighty'o, so overall the rewritten the expression so that the GCF is factored completely is 3y(x^3+4x−x^2−4)? @asnaseer

Answer 37

(refresh page to remove question marks)

Answer 38

yes :)

Answer 39

Thanks, but do you mind helping me on another one?

Answer 40

yw :)

<<<---- please post each question separately on the left

I will try to help but if I am busy with other things then be assured that there are plenty of very good helpers on this site who will be more than happy to help :)

Answer 41

Oh ok, will do :) Thanks a ton for the help :)

Answer 42

again - yw :)