Evaluate the following: [(x+y)^2]/[4x^2-y^2] = ??? if x = 3 and y = -5d. I got the following: [(3+(-5d))^2]/[4(3)^2-(-5d)^2] => [9-30d+25d^2]/[36+25d^2]
Does it end up with: 9-30d/36?
Equation View: Evaluate the following if x = 3; y -5d \[\frac{ (x+y)^{2} }{ 4x ^{2}-y ^{2} }\] I got the following: \[\frac{ (3+(-5d))^{2} }{ 4(9) ^{2}-(-5d) ^{2} }\] \[\frac{ 9-30d+25d^{2} }{ 36+25d^{2} }\] I cant figure out the next step.
Factoring it..
For the numerator rearrange it to \(\ 25d^{2}-30d+9 \)
And we use the perfect square trinomial which is \(\ A^2 - 2AB + B^2 = (A - B)^2\)
Do you get that? @Sadworld @~ :P
In this example we have \(\ \color{blue}{ A = 5x }\) and \(\ \color{red}{ B = 3 }\)
So \(\ 25x^{2}-30x+9 = ( \color{blue}{ 5x } - \color{red}{ 3 } )^2\)
So you mean I should factor it? My answer would bet the same as the question: (3+(-5d))^2
I'm asked to simplify further. I'm wondering if 25d^2 cancel each other out making the it 9-30d/36
Looking at the denominator from the very beginning: [4x^2-y^2] = [36 - ( - 5d ) ^2 ] = [ 36 - ( + 25 d^2) ] = [ 36 - 25 d^2 }
I think you have the denominator as [ 36 + 25 d^2 } Not sure, but please check. @Sadworld
I see, you're right
What I should do next after solving it? I'm asked to simplify further.
That denominator will not factor over the real numbers.
Let me look again at the numerator.
Just in case, would you double-check and see if you posted the problem correctly?
Could you paste the problem here?
Yeah, the problem is correct. I don't think it can be factored further. I just want to be sure. Just a 2nd copy of the problem: If x = 3 and y = -5b \[\frac{ (x+y)^{2} }{ 4x ^{2}-y ^{2} }\]
Can you divided with 1/common deno?
basically cross multiply?
y = -5b ? or y = -5d ? as stated in the original post?
It's y = -5d; typo, sorry
I don't think the expression will simplify. Were you told that it would?
Nope, got it in a problem book. Just says to simply as much as possible. Cross multiply with itself isn't a possibility?
Cross multiply when there is an equation. There is no equation here.
I am going to rework the problem from the beginning and see if I get the same answer. I will report back here on my result, okay?
Sure thing, I'll be online for awhile. I can check up tom is it takes longer.
It should go fast.
BTW, I've factored/simplified the originals question, dunno if it matters: \[\frac{ (x+y)(x+y) }{ (2x+y)(2x-y) }\]
No common factors upstairs and downstairs. Okay, my re-check gives Numerator: (3 - 5d)^2 Denominator: (36 - 25 d^2) = ( 6 + 5d) (6 - 5d)
same here
I think that is the answer. Usually, these books read "simplify if possible" so as not to make us think the result should simplify.
Okay, thanks. So I've been knocking on my head for no reason. Well better try then be sorry :)
The "cleanest" way to write this,I think, is with Numerator: (3 - 5d)^2 Denominator: (36 - 25 d^2)
Right, I agree. And, we did find a sign error even if it did not allow us to strike out factors.
Hey, if this turns out to be a different answer, would you post here and let me know. I just cannot imagine what a different answer would be.
Sure thing, if there's no answer then we got it right :D
I'm laughing at that. And, I enjoyed exchanging math ideas with you. Let's do it again sometime, okay?
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