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OpenStudy (anonymous):
@SolomonZelman I have no clue on how to do perpendicular ones o; I only have 2 of them to do though
OpenStudy (michele_laino):
please note that the slope m of your line is :
\[m=-\frac{ 1 }{ 3 }\]
because product of the slopes of perpendicular lines has to be equal to 1
so,please apply the subsequent equation:
\[y-y _{0}=m(x-x _{0})\]
where (x_0,y_0) is your point and m=-1/3
OpenStudy (michele_laino):
oop the product of the slopes of perpendicular lines has to be equal to -1
OpenStudy (anonymous):
o;
OpenStudy (dtan5457):
Yes. A perpendicular slope of any slope is flipped and negated. If the original slope was -1/3, your perpendicular slope would be 3/1.
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OpenStudy (anonymous):
1/12 is the answer
OpenStudy (dtan5457):
Do you know where to go from there?
OpenStudy (anonymous):
thats what i got
OpenStudy (anonymous):
y=3x+1/12
OpenStudy (michele_laino):
@dtan5457 please note that the original slope is 3
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OpenStudy (dtan5457):
@Michele_Laino
I am aware. I was just setting an example.
OpenStudy (michele_laino):
oops.. sorry @dtan5457
OpenStudy (anonymous):
thanks to both of u :D
OpenStudy (anonymous):
you guys have time for 1 more?
OpenStudy (michele_laino):
thank you! @ayeitsJenni.
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OpenStudy (michele_laino):
yes!
OpenStudy (anonymous):
passes through -1,5 and is perpendicular to y=-5/2x+2
OpenStudy (anonymous):
im not good with fractions.
OpenStudy (michele_laino):
please, note that if I have this fraction: 5/7
the inverse fraction is: 7/5
OpenStudy (michele_laino):
so what in the inverse fraction of 5/2?
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OpenStudy (anonymous):
don't you only inverse at the end? when you find the slope which is b..
OpenStudy (anonymous):
2/5
OpenStudy (michele_laino):
ok! now please change its sign and you will get your slope!
OpenStudy (anonymous):
-2/5?
OpenStudy (michele_laino):
that's right!
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OpenStudy (michele_laino):
now, please apply the formula above, where, this time, (x_0,y_0) is the point (-1,5)
OpenStudy (michele_laino):
and m=-2/5
OpenStudy (anonymous):
I don't really get none of this >_<
OpenStudy (anonymous):
don't you use y=mx+b?
OpenStudy (michele_laino):
please, you have to apply this formula:
\[y-y _{0}=m(x-x _{0)}\]
where m=-2/5 as you wote, and (x_0,y_0)=(-1,5)
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OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
so its y - 5 = -2/5(x--1)
OpenStudy (michele_laino):
ok! the parentheses, is:
\[(x-(-1))=(x+1)\]
OpenStudy (anonymous):
y-5 = -2/5 (x+1)
OpenStudy (anonymous):
thats the equation now?
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OpenStudy (michele_laino):
yes! it is!
OpenStudy (anonymous):
oh awesome
OpenStudy (anonymous):
what do i do now
OpenStudy (michele_laino):
you have to perform multiplication, namely:
\[-\frac{ 2 }{ 5 }(x+1)=...\]
OpenStudy (anonymous):
-2/5x + -2/5
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