Question

How do you express the following in algebraic expression: The value of a number increases by 22 every time another number doubles? I got: x+22/2y.

Answer 1

Why divide?

Answer 2

was thinking in terms of X per y which's normally express as x/y example km/h. But I might be confusing my physics with math.

Answer 3

The other one I have in mind is 2x = y+22 but it doesn't seem right.

Answer 4

This is harder than it looks,lol..

Answer 5

I know right, I'm thinking it has some kind of factorial just can't remember the formula.

Answer 6

How do express a number that doubles every time? Exponents right?

Answer 7

yes

Answer 8

then how do you express a number increasing by 22 corresponding to the exponent of another number?

Answer 9

@Nnesha @Jhannybean

Answer 10

would there be more than 2 variables??

Answer 11

I got a table here representing the growth but I've to express function... give me a moment to write it down.

Answer 12

alright. im really curious about this.

Answer 13

1 = x; 2 = x+22; 4 = x+44; etc.

Answer 14

That's it really, it asks for the table to be express as an algerbraicly i.e. x-110w.

Answer 15

How about: \[x^{2} = y+22x\]

Answer 16

can't be..because that means that the number determines how many times you add 22..

Answer 17

if x=5 for example in that equation, it's doubled once but 22 times 5?

Answer 18

You right, how about: \[x ^{y}=z+22y\]

Answer 19

the closest i can think of is

\[x+22y=r^y \]

Answer 20

lols, we got the same idea.

Answer 21

the problem with that is when it's doubled once.. if y=1 aka the number isn't doubled, the other side still adds the 22.

Answer 22

if it's doubled twice or y=2, then 22 gives it out 2 times instead of 1...

Answer 23

\[If: x = 2, y \neq 1\]\[x ^{y} = z + 22y\]

Answer 24

\[2^{5} = z +22(5)\]

Answer 25

looks right to me...

Answer 26

How about...
\[x+22(y-1)=r^y{-1}\]

Answer 27

double your equation once, replace y with 2

Answer 28

it doubles correctly on the exponent but gives 44 for only one double :/

Answer 29

since 1 = x, 2 = x+22, 4 = x+44

Answer 30

my equation doesn't work either, lol.

Answer 31

\[2^{2} = z + 22(2) = z\]

Answer 32

z + 44

Answer 33

but the number doubled once

Answer 34

it's suppose to be z+22

Answer 35

but 2 is already a double. The problem starts at 1. So:

If x = 2, y /= 1 and x-1 = z then the equation stands, I think.

Answer 36

Else we would need sigma

Answer 37

xy=z+22y

1 doesn't work

^2 is a double.

y for 22 is suppose to =1, but it would be 2..

Answer 38

1 double=+22, not 44

Answer 39

Try this one

Answer 40

\[x+22(y-2)=r^{y-1}\]

Answer 41

That would work with a single double.

Answer 42

3-1=2

one double

(3-2)=1

22

Answer 43

lemme try it

Answer 44

it really looks like it works lol

Answer 45

As long as

\[y \neq 0,1\]

Answer 46

x is the base amount, y is the exponent and r is the number being doubled?

Answer 47

just making sure I got the variables right...

Answer 48

x=the first number
r=the 2nd number

y to be honest does NOT represent the amount of times being doubled

Answer 49

the equation when being solved would put your statement true.

Answer 50

but y=any# that makes your equation true

which is not 0,1

Answer 51

it doesn't really "stand" for anything

Answer 52

r would colapse if it's 1

Answer 53

yes that's why
y>1

Answer 54

\[x+22(5-2)=1^{5-1}\]

Answer 55

\[r \neq 1\]

Answer 56

r>1
y>1

Answer 57

to be honest this question is full of ****

Answer 58

With that, my equation would have work. Lols, I love the challenge imo. Solving such pellet makes me feeling like Hawkins

Answer 59

*problem

Answer 60

yes, but say your question doesn't allow restrictions then that question will end your life

Answer 61

We can assume 1 = x, 2 = x + 22 since my equation starts at 2 then it's valid.

Answer 62

We need 3rd person, we're just bouncing each others idea.

Answer 63

not sure what you mean by x=?

Answer 64

\[2^{2} = 4; 2^{3} = 8; etc\]

Answer 65

x = 1 is the base
x + 22 = 2

Answer 66

x + 44 = 4
x + 66 = 8

Answer 67

hence: \[x + 22(y) = z ^{y}\]

Answer 68

So what you think @JoannaBlackwelder

Answer 69

I'm working on it, just a sec.

Answer 70

your right the values would not equal to eachother

Answer 71

I don't think you can make this happen in an expression. It needs an equation.

Answer 72

I think I got my vocabs wrong, I think I meant equations all along.

Answer 73

The value of a number increases by 22 every time another number doubles:

If \[z = 2, y \neq 1, z-1 = x\] then
\[x + 22(y) = z ^{y}\]

Answer 74

Just seems right to me but I'm not sure...
\[1 = x\]\[2 = x + 22\]\[2^{2} = x+22(2) = 4 = x+44\]\[2^{3} = x+22(3) = 8 = x+66\]