Sorry if this is hard to understand. Fractions are hard to write. ((4)/(3a-5))+((3a^2+38a+36)/(25a-9a^3))=((3)/(3a+5))
ok
\[\frac{ 4 }{ 3a-5 } + \frac{ 3a^2+38a+36 }{ 25a-9a^2 } = \frac{ 3 }{ 3a+5 }\]
did i get that right?
Yeah
ok
yeah that looks right
i would multiply everything by a common denominator , so you can get rid of the fractions
oh thats a 9a^3 in the bottom right?
Yeah. its cubed. thats also part of the problem why i cant figure it out
\[25a-9a^3 = -a(9a^2 -25) = -a(3a-5)(3a+5)\]
Wouldn't you factor all of them
sometimes problems from books and homework give you clues, so i would have tried the other denominators (3a-5)(3a+5) as factors of the cubed term first
so multiply everything by -a(3a-5)(3a+5)
ok hang on one sec
ill starty typing it out
wait i should each fraction by the thing above or each denominator?
multiply both sides by a ratio of 1 \[\frac{ -a(3a-5)(3a+5) }{ -a(3a-5)(3a+5) }\]
all the fractions will be over the common denominator after that ,,
oh ok thanks
ill start typing it up
\[\frac{ -4a(3a+5) }{ -a(3a-5)(3a+5) } + \frac{ (3a^2+38a+36) }{ -a(3a-5)(3a+5) } = \frac{ -3a(3a-5) }{ -a(3a-5)(3a+5) }\]
see if you cancel out terms in the numerators and denominators, you are back to the starting problem
so now that everything is over a common denominator, you can equate the numerators, same as if you multiplied both sides by -a(3a-5)(3a+5) to cancel the denominators,
\[-4a(3a+5) + (3a^2+38a+36) = -3a(3a-5)\]
multiply out the terms, and combine like powers
\[-12a^2 - 20a +3a^2+38a+36 = -9a^2+15a\]
u with me ?
Yeah I follow.
see the a^2 terms cancel , you have -9a^2 on both ends
you left with 18a+36=15a which leads to 3a=-36 which means a = 12
-12
i mean negative 12
ill do a quick chek on my calc to see if any mistakes were made.. one sec
I think that's right because -12 is answer b
yep a=-12 is it
Thanks!
welcome, anytime
just remember if it is a prob from a book or test or something, and you need to factor to get a common denominator, look at the other denominators as they are probably the factors..
like the (3a-5)(3a+5) in this prob
ok got it
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