Question

Medal & Fan

Answer 1

Part A: Factor 3x2y2 - xy2 - 2y2. Show your work.
Part B: Factor x2 + 6x + 9. Show your work.
Part C: Factor x2 - 25. Show your work.
Part D: Do the polynomials in parts A, B, and C have a common factor? Explain your answer.

Answer 2

@partygirl

Answer 3

@ShadowLegendX

Answer 4

@FireWolfSpirit

Answer 5

@TheMysteriousRainbowPegasus

Answer 6

@SolomonZelman

Answer 7

what have you atempted?

Answer 8

yes

Answer 9

i really

Answer 10

only need help with d

Answer 11

tell me what you got for parts A, B, and C.

Answer 12

ok
one sec

Answer 13

a: y^2((3x+2)(x-1))
b: x^2+6x+9
c: x^2-25

Answer 14

i was thinking x, but im confused

Answer 15

Parts:
A \(\large\color{black}{ 3x^2y^2 - xy^2 - 2y^2 }\)
B \(\large\color{black}{ x^2 + 6x + 9 }\)
C \(\large\color{black}{ x^2 -25 }\)

you need to factor each part.

Answer 16

will start from part C, okay?

Answer 17

wait

Answer 18

I can wait, sure...

Answer 19

i have it

Answer 20

i gave you the wrong thing

Answer 21

?? ... t

Answer 22

a: is factored
b: (x+3)^2
c: (x+5)(x-5)

Answer 23

for part A you can factor out \(\large\color{black}{ y^2 }\)

Answer 24

y^2((3x+2)(x-1))

Answer 25

and then factor the inner part, yes,
\(\large\color{black}{ y^2(x-1)(3x+2) }\)

Answer 26

So you get:
A: \(\large\color{black}{ y^2(x-1)(3x+2) }\)
B: \(\large\color{black}{ (x+3)^2 }\)
C: \(\large\color{black}{ (x+5)(x-5) }\)

Answer 27

do A B and C have any common factors?

Answer 28

x

Answer 29

x is not a factor

Answer 30

ok

Answer 31

then no

Answer 32

the factors of part A are:
\(\large\color{black}{ \color{red}{y^2}\color{blue}{(x-1)}\color{green}{(3x+2)} }\)

Answer 33

yes, they have no factors in common.
part A has: \(\large\color{black}{ y^2 }\) , \(\large\color{black}{ x-1 }\) and \(\large\color{black}{ 3x+2 }\)
part B has: \(\large\color{black}{ x+3 }\) twice
part C has: \(\large\color{black}{ x+5 }\) and \(\large\color{black}{ x-5 }\)