Question

Susan
begins counting backward from 1298 by 4's, saying one number every 5 seconds. At
the same time, Jim begins counting forward from 171 by 3's, saying one number every 5
seconds. What number will they both say at the same time?
(A) 640
(B) 644
(C) 648
(D) 650
(E) 654

Answer 1

for the first one you can do
1298 - 4 ( t/5) , if you want to use t = seconds

Answer 2

Susan decreases by 4 every 5 seconds
t = 5 seconds intervals

Susans # = 1928 - 4*t

Answer 3

both count in the same interval of 5 seconds

Answer 4

So what would the answer be??

Answer 5

Jims # = 171 + 3*t

Answer 6

you want jims # to equal susan's #

Jim # = susan #

Answer 7

its simpler to use t = 5 second intervals :) so i agree with Dan

Answer 8

soooooo the answer??

Answer 9

Jim # = Susan #

171 + 3t = 1928 - 4t

solve for time t first

Answer 10

I can help you get to the answer, im not paid to do the work for you

Answer 11

how much do you want?

Answer 12

lol jk

Answer 13

ahahah

Answer 14

i wish,

Answer 15

ok thx

Answer 16

can you solve that for t?

Answer 17

171 + 3t = 1928 - 4t

Answer 18

i believe sooo

Answer 19

is the answer 648?

Answer 20

i misstyped one number

171 + 3t = 1298 - 4t

i get t = 161

Answer 21

so after 161 intervals of counting , each person will be at the same number

Answer 22

so the answer is 654

Answer 23

From Above:

Susans # = 1298 - 4t = 1298 - 4(161) = 654

Jims # = 171 + 3(161) = 654

They both meet at 654 after 161 intervals of counting, or 161*5 = 805 seconds

Answer 24

OK thanks a lot

Answer 25

welcome

Answer 26

:)

Answer 27

I became a fan

Answer 28

thanks, feel free bother me whenever i am on with @DanJS