Question

What is the 185th digit in the
following pattern 12345678910111213141516....
(A
) 0
(B) 5
(C) 7
(D) 8
(E) 9

Answer 1

A is 0

Answer 2

Can you see what the pattern is?

Answer 3

yes

Answer 4

Then what's troubling you?

Answer 5

everything

Answer 6

Tell me what the pattern is, lol.

Answer 7

it is counting up with by 1s

Answer 8

Lol relax relax this is simple you could do it :)

Answer 9

did you try writing out the rest of the digits.?

Answer 10

nope

Answer 11

Then do it. -.-

Answer 12

OHHHHHHHHH ok

Answer 13

Thats a slow method though

Answer 14

The first 9 numbers have 1 digit the next more than enough have 2 digits each

Answer 15

it will take 5 minutes

Answer 16

oh, I thought that every digit is a separate term in the sequence....
then:
\(\large\color{blue}{d=1}\) and \(\large\color{blue}{a_1=1}\)

Answer 17

but a_10=1 so d isnt really 1

Answer 18

ok, but what would you do if they asked for the 8726394920123 th digit dtan?

Answer 19

I got it is 7

Answer 20

i would get a lot of paper ready

Answer 21

nope, just logic

Answer 22

haha, or you could sum it up in a inch long formula

Answer 23

wait, so I initially thought correctly, then.
it is, \(\large\color{black}{ 1,2,3,4,5,6,7,8,9,1,0,1,1,1,2,1,3,1,4,1,5,1,6 }\)

Answer 24

just counting up 11 12 13 14 15 16

Answer 25

there are how many 1 digit numbers, then how many 2 digit numbers, etc

Answer 26

^right

Answer 27

1...10 = 11 numbers
11...20 =20 numbers start from1
21....30= 20 numbers. start from2
and so on...
if you stop at "start from 8, you have 171th number,
now just count your finger to get 185 th number.

Answer 28

there are 9 one digit numbers
there are 100 - 10 + 1 two digit numbers

Answer 29

http://oeis.org/

Answer 30

http://oeis.org/search?q=1%2C2%2C3%2C4%2C5%2C6%2C7%2C8%2C9%2C1%2C+0%2C1%2C1%2C1%2C2&sort=&language=english&go=Search

Answer 31

no, I am thinking it is:
\(\large\color{black}{ 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16 }\)
and you need the 185th digit (not term but digit).

so firstly you need to find where will the 185th digit be:
1) first 9 terms = 9 digits
2) + second 9 terms = 9 digits + 90
99 digits so far:
we need 86 more digits
each term goes by 2 digits, so this is 43 more term.

Answer 32

So, it is going to be: the last digit of the \(\large\color{black}{ (9+9+43)th }\) term

Answer 33

last digit of \(\large\color{black}{ 61st }\) term

Answer 34

There are 9 one-digit numbers

So that leaves 185 - 9 = 176 digits left over. Divide by 2 to get: 176/2 = 88

So there are enough digits to form 88 two-digit numbers. If you add 88 to 10, you get 10+88 = 98. However, going from 10 to 98 yields 89 numbers (98-10+1 = 89). To fix this, we just take a step back and land on 97 instead.

Answer 35

yeah, we all have different interpretations of the question...

Answer 36

From 1 to 9 ---> 9 digits
185 − 9 = 176

We need 176th digit after the first 9
This will be 2nd digit of 88th number after 9
i.e. 2nd digit of 87

185th digit = 7

Answer 37

there are no parentheses in the original expression above, so I separated each digit by a comma

Answer 38

my interpretation is not any of the options, (because 1 is not a choice) so i guess I was wrong....

Answer 39

here is a nice table for the list of digits from 1 to very large number
http://oeis.org/A033307/b033307.txt

Answer 40

note that the list starts at n=0, instead of n=1. so the 184th entry is going to be the 185th digit in the original question