With these four complex numbers, evaluate:
(for more medals :)) )

Question

With these four complex numbers, evaluate:
(for more medals :)) )

anonymous · Answer

attachment

anonymous · Answer

THE VALUES I GOT:

$$(conjugate of AB )^{4} = -27765.67507-j101916.2112$$
$$\log_{2}(C+D) = 3.519099971+j1.155941712 $$
$$\log_{B}A = 0.5409332173+j0.7866286902 $$
$$\ln (D ^{1/4}) = 0.2746530722-j0.03085$$


$$\sin A + \cos B = \sin(2)\cosh(j3) - jcos(2)\sinh(j3)$$
$$+ \cos(4.3301)\cosh(j2.5) + jsin(4.3301)\sinh(j2.5)$$

ganeshie8 · Answer

its (A*cojugate of B )^4 right ?

anonymous · Answer

$$(\tanh(\frac{ A }{ B }))^{2-j3} = \frac{ e ^{0.3167-j0.0223 - e ^{-0.3167+j0.0223}} }{ e ^{0.3167-j0.0223}+e ^{-0.3617+j0.0223} }$$
$$ \sinh^{-1} (CC_(conjugate)) =  5.288461917$$

anonymous · Answer

ah yeah wait :)

ganeshie8 · Answer

for $(A\overline{B} )^4$ : http://www.wolframalpha.com/input/?i=%28%282%2Bi3%29*%285e%5E%28i+pi%2F6%29%29%29%5E4

ganeshie8 · Answer

click again ^

anonymous · Answer

i got that one too :DD

ganeshie8 · Answer

your answer is right for $\log_2(C+D)$ : http://www.wolframalpha.com/input/?i=log_2+%2810e%5E%28i+pi%2F3%29%2B3e%5E%28-i+0.1234%29%29

ganeshie8 · Answer

similarly you can check other parts using wolfram