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how to solve for cosh(3i)?
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coshx = (e^x + e^-x)/2 so just substitute x=3i
oh thanks! :)
can't solve it using a sci. calculator tho..
no you can't! need to convert e^3i to x+yi & e^-3i to u+vi
cosh(i*x) = cos(x)
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using euler's formula
convert? isn't 3i already in rectangular form? :)
no. e^3i is in polar form. but Dan has given it away
\[\cosh(i*x) = \frac{ 1 }{ 2 }[e ^{ix} + e ^{-ix}] = \cos(x)\]
e^3i = cos3 + isin3 and e^-3i = cos(-3) + isin(-3) so (e^3i + e^-3i)/2 = cos3
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all u have to know is euler's formula
now you can use a calculator :)
also you can use the fact that cos(-x) = cos x
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