Question

3.Find the range of values of x of each of the following.
@Directrix @Jhannybean @hartnn @Ganpat

Answer 1

a)\[12>x(x-4)\]

Answer 2

Take RHS of equation..

substitute different values of x, to get a solution less than 12..

Along with positive also consider negative values for equation.. like -1, -2

Answer 3

or solve the following equation :p

x2 - 4x - 12 <0

Answer 4

x=12 and x=4

Answer 5

but the answer say is \[-2< x<6\] @Ganpat

Answer 6

x2 - 4x - 12 <0
x2 - 6x + 2x -12 <0
x(x-6) +2(x-6) < 0
(x-6) (x-2) < 0

x <6 and x>2

some what like this ?

Answer 7

not sure @Ganpat

Answer 8

well !! did u understand what i did ?

Answer 9

how u get -6x? @Ganpat

Answer 10

x2 - 4x - 12 <0

sum should be -4
& product should be -12

possibilites -6 + 2 = -4 & -6 * -2 = 12

so x2 - 6x -2x -12 = 0

Answer 11

This should be:

( x-6 ) (x+ 2) < 0

Answer 12

The product of two quantities is less than 0 (think negative).

Positive * Negative is Negative

OR

Negative * Positive is Negative

Answer 13

Two Cases

( x-6 ) > 0 AND (x+ 2) < 0

OR

( x-6 ) < 0 AND (x+ 2) > 0

Answer 14

@MARC_ You have work to do here.

Answer 15

thnx @Directrix

Answer 16

and @Ganpat