Question

Please help!
Find the Cartesian form of

Answer 1

Thank you!

Answer 2

\[r(1 + \sin \theta) = a\]

Answer 3

you are welcome dear

Answer 4

is \(a\) a constant?

Answer 5

yes, I think so

Answer 6

if you multiply you can get
\[r+r\sin(\theta)=a\] and since \\[r\sin(\theta)=y\] you can rewrite as \[r+y=a\]

Answer 7

after that i think the best you can do is to rewrite
\[r=\sqrt{x^2+y^2}\] gets you
\[\sqrt{x^2+y^2}+y=a\] then maybe some algebra to get rid of the radical
might be an easier way, but i am not sure

Answer 8

yeah,
\(\sqrt{x^2+y^2} = a-y\)

squaring that would look nice :)

Answer 9

Thank you so much! :)

Answer 10

you are welcome dear